What is the velocity of the 100 kg cart at point b?

A bag of wheat 60kg find the height to which it is lifted so that its potential energy is 3000j

Bond [772]

PE = mgh
m = 60 kg
g = 10 m/s
h = X
_______
3000 = 60×10×X = 5 m

6 0

4 years ago

Label the producers and consumers, then label the different types of consumers.

sdas [7]

The base of the pyramid has the producers and everything else above the base falls under the consumers category i.e the locusts,frogs and the snake. The grass is the producer, the locust is a consumer, the frog is a special type of omnivore, termed the "life-history omnivore" since they eat both plants and animals but at different times in their lives. In this case they are just omnivores and lastly, the snake is a carnivore.

3 0

3 years ago

A cube, whose edges are aligned with the , and axes, has a side length . The field is immersed in an electric field aligned with

Ivenika [448]

Complete Question

Complete Question is attached below

Answer:

$q=1.558*10^{-9}c$

Explanation:

From the question we are told that:

Side length s=1.13m

Left field strength $E_l=784.75N/m$

Right field strength $E_r=776.38 N/m$

Front field strength $E_f=725.5 N/m$

Back field strength $E_b=749.54 N/m$

Top field strength $E_t=944.95 N/m$

Bottom field strength $E_{bo}=1082.58 N/m$

Generally, the equation for Charge flux is mathematically given by

$\phi=EAcos\theta$

Where

Theta for Right,Left,Front and Back are at an angle 90

$cos 90=0$

Therefore

$\phi =0$ with respect to Right,Left,Front and Back

Generally, the equation for Charge Flux is mathematically also given by

$\phi=\frac{q}{e_o}$

Where

$Area =L*B\\\\A=1.13*1.13\\\\A=1.2769m^2$

Therefore

$Q_{net}=E_{bo}Acos\theta_{bo} +E_tAcos\theta_t$

$Q_{net}=1082.85*1.2769*cos0=944.95*1.2769cos (180)$

$Q_{net}=176N/C m^2$

Giving

$q=\phi*e_0$

$q=176N/C m^2*1.558*10^{-12}c$

$q=1.558*10^{-9}c$

4 0

3 years ago

incline plane is given length 12m,load 600 newton,effort 200 Newton, Height 3 metre find its velocity ratio and mechanical advan

Salsk061 [2.6K]

Answer:

i. The velocity ratio of the plane is 4.

ii. The mechanical advantage of the plane is 3.

Explanation:

i. The velocity ratio (VR) of an inclined plane is ratio of its length to the height. It is given as;

VR = $\frac{length of the plane}{height}$ = $\frac{l}{h}$

Given: l = 12 m, L = 600 N, E = 200 N, h = 3 m.

So that,

VR = $\frac{12}{3}$

= 4

The velocity ratio of the plane is 4.

ii. Mechanical advantage (MA) expresses the relationship between the load overcome to effort applied.

MA = $\frac{Load}{Effort}$ = $\frac{L}{E}$

= $\frac{600}{200}$

= 3

The mechanical advantage of the plane is 3.

Therefore, the velocity ratio of the inclined plane is 4, and its mechanical advantage is 3.

7 0

3 years ago

_____ variables are manipulated by the experiments

nikitadnepr [17]

Answer:

dependent variables

Explanation:

dependent varibeles are the thing you're measuring and independent variables are the thing you change in the exeriment to get a different dependent variable.

may I get brainliest please? :)

3 0

4 years ago