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Black_prince [1.1K]
2 years ago
14

What is the velocity of the 100 kg cart at point b?

Physics
1 answer:
Gre4nikov [31]2 years ago
8 0
I believe the answer is c
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How far does a car travel as it accelerates from 12 m/s to 18 m/s at 3 m/s??
yulyashka [42]

Answer:

Explanation:

I ASSUME you mean acceleration is 3 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (18² - 12²) / (2(3))

s = 30 m

to verify we can see that the acceleration time is

t = (18 - 12) / 3 = 2 s

s = 0 + 12(2) + ½(3)2² = 30 m

4 0
2 years ago
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi
marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0
3 years ago
Which one A, B, C, D or the last one?
Finger [1]

Answer:

C

Explanation:

Answer is C.

8 0
3 years ago
A pendulum is swinging back and forth with no non-conservative forces acting on it. At the highest points of its trajectory, the
Vesna [10]

Answer:

K = U ( b )

Explanation:

The expression that describes the kinetic and potential energies at the point mid-way between to the highest and lowest points is  K = U

this is because at the midpoint between the highest point and the lowest point the height is expressed as( h/2) therefore potential energy at that point is expressed as m*g*h/2 therefore the remaining energy at this point will be considered the kinetic energy which will be = m*g*h/2 as well hence at midpoint Kinetic energy = potential energy

6 0
3 years ago
A 60kg man jumps off a 30 foot building. Assuming he falls from rest and there is negligible air resistance, how long will it ta
Dmitriy789 [7]

Answer:

1.37 seconds before.... splat !

Explanation:

y = y0 + v0 t + 1/2 a t^2      y0 = 30       y = 0

                    v0 = 0 ( from rest)

                            a = - 32.2 ft/s^2

0 = 30 - 1/2 * 32.2 * t^2

t=1.366 seconds                   <u>  Note that   mass   is irrelevant.</u>

5 0
1 year ago
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