Answer:
1309.1 Nm
Explanation:
Torque is given as a product of Moment of innertia and acceleration hence
T=Ia where T is torque and a is acceleration
To get acceleration, it is rate of change of speed per unit time hence 
where v and t represent velocity and time respectively while subscripts f and i represent final and initial respectively. Also, I is given by 
where m js mass and r is radius hence the net torque can now be written as
By substituting the given figures then
Answer:
156.26N
Explanation:
The data needed are incomplete. Let the acceleration of the body be 3.5m/s²
Other given parameters
Mass = 1.35×10^1 = 13.5kg
coefficient of friction between the tires and the road = 0.850
Acceleration due to gravity = 9.8m/s²
According to Newton's second law:
Fnet = ma
Fnet = Fapp - Ff
Fapp is the applied force
Ff is the frictional force = umg
The equation becomes:
Fapp - Ff = ma
Fapp-umg = ma
Fapp - 0.85(13.5)(9.8) = 13.5(3.5)
Fapp - 109.0125 = 47.25
Fapp = 47.25+109.0125
Fapp = 156.2625N
Hence the applied force that caused the acceleration is 156.26N
Note that the acceleration of the car was assumed. Any value of acceleration can be used for the calculation.
Answer:
Explanation:
I'm not sure you can do this without just a bit more information. I can tell you what the mass of the water is when the rocks are removed. When we know that, we know the volume of the water that was displaced. whether or not this is enough information to determine the volume of the box, I'm not sure.
400 grams raises the box 1 cm.
The density of water = 1 gm / cm^3
400 grams of water = 400 mL or 400 cm^3
The volume of the displaced water = 400 cm^3
The volume a slice from the square prism is B*h
B = 400 cm^2
h = 1 cm
If the base is 400 cm^2 then each side is
s^2 = 400
sqrt(s^2)= sqrt(400)
s = 20
The volume of the box is 20^3 = 8000 cm^3
