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AURORKA [14]
2 years ago
6

4(3 + 5) - 3 x 9² ?​

Mathematics
1 answer:
tiny-mole [99]2 years ago
7 0

Answer:

  • - 211

Step-by-step explanation:

  • 4(3 + 5) - 3 x 9² =
  • 4(8) - 3(81) =
  • 32 - 243 =
  • - 211
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If a person sees 7 pennies, 6 Nickels, 4 dimes, and 6 Quarters, and he picks 1 of each, how many different combos can there be?
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(- 8) + 5 + 4 + (- 2) = resuelve
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Answer: -1

BRAINLIEST PLZZZZZZZZZ

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Step-by-step explanation:

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If you change the slope in the equation y= 5x + 7 to y = 2x + 7 how will its graph change?
Anuta_ua [19.1K]
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And y=2x+7 has a slope of 2 (the number before the x)

So as you move from left to right, the one with greater slope will increase y value faster. Just like if you were climbing two mountains. If you went for 1 kilometre up a really steep mountain, you would be higher up than if you went for 1 kilometre up a less steep mountain.

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Answer B
6 0
3 years ago
Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. What perce
LenKa [72]

Answer:

14.28% of individual adult females have weights between 75 kg and 83 ​kg.

92.82% of the sample means are between 75 kg and 83 ​kg.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of adult females are normally distributed with a mean of 79 kg and a standard deviation of 22 kg. This means that \mu = 79, \sigma = 22.

What percentage of individual adult females have weights between 75 kg and 83 ​kg?

This percentage is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 75. So:

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 79}{22}

Z = 0.18

Z = 0.18 has a pvalue of 0.5714.

X = 75

Z = \frac{X - \mu}{\sigma}

Z = \frac{75- 79}{22}

Z = -0.18

Z = -0.18 has a pvalue of 0.4286.

This means that 0.5714-0.4286 = 0.1428 = 14.28% of individual adult females have weights between 75 kg and 83 ​kg.

If samples of 100 adult females are randomly selected and the mean weight is computed for each​ sample, what percentage of the sample means are between 75 kg and 83 ​kg?

Now we use the Central Limit THeorem, when n = 100. So s = \frac{22}{\sqrt{100}} = 2.2.

X = 83

Z = \frac{X - \mu}{s}

Z = \frac{83 - 79}{2.2}

Z = 1.8

Z = 1.8 has a pvalue of 0.9641.

X = 75

Z = \frac{X - \mu}{s}

Z = \frac{75-79}{2.2}

Z = -1.8

Z = -1.8 has a pvalue of 0.0359.

This means that 0.9641-0.0359 = 0.9282 = 92.82% of the sample means are between 75 kg and 83 ​kg.

8 0
3 years ago
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