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Svetlanka [38]
3 years ago
14

Isotopes have

Chemistry
1 answer:
Feliz [49]3 years ago
7 0

Answer:

question 1 answer is b

Explanation:

istopes equal to same atomic number but different mass number

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What are the atomic number and mass number of this atom
lina2011 [118]
No diagram is given therefore I cannot answer however, use this for reference.
The atomic mass of an atom would be the number of protons PLUS the number of neutrons. Because this atom shown has 6 protons and 6 neutrons, they add up to 12. In this case, the atomic mass of this atom is 12. Atomic number is the number of protons in an atom, in this case it is 6. The atomic number is 6.

5 0
3 years ago
Which of the following lists of elements are in the same PERIOD? *
yuradex [85]
Ca, V, Cu, Kr
Remember a period is a the horizontal rows in the Periodic Table.

5 0
3 years ago
Titanium metal is used as a structural material in many high-tech applications such as in jet engines.
Elza [17]

Answer:

a.Cp=0.523

b.Cp=25.02\frac{J}{mol^\circ C}

Explanation:

a. First, we solve the specific heat equation as follows:

Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523

b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:

Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}

3 0
3 years ago
How many moles of carbon are in 7.00 x 1023 atoms of carbon?
Andru [333]

Answer:

<h2>1.16 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{7}{6.02}  \\  = 1.162790....

We have the final answer as

<h3>1.16 moles</h3>

Hope this helps you

8 0
3 years ago
What conversion factor is needed to calculate the number of atoms in 8.6 moles of Aluminum?
Rudiy27

Answer:hey did you ever get an answer? I need it for this exam

Explanation:

7 0
3 years ago
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