Answer:
The answer to your question is 6.77 atm
Explanation:
Data
Pressure 1 = P1 = 7.5 atm
Temperature 1 = T1 = 65°C
Pressure 2 = P2 = ?
Temperature 2 = T2 = 32°C
Process
-Use Gay-Lussac law to solve this problem
P1/T1 = P2/T2
-Solve for P2
P2 = P1T2 / T1
-Convert temperature to °K
T1 = 65 + 273 = 338°K
T2 = 32 + 273 = 305°K
-Substitution
P2 = (7.5 x 305) / 338
-Simplification
P2 = 2287.5 / 338
-Result
P2 = 6.77 atm
PV=nRT
Here
P1/T1= P2 / T2
1 torr=133 pascal
600 *133 /215 = 750 *133 / t2
T2= 268.75 K
Answer:
44 grams of CO₂ will be formed.
Explanation:
The balanced reaction is:
C + O₂ → CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- C: 1 mole
- O₂: 1 mole
- CO₂: 1 mole
Being the molar mass of each compound:
- C: 12 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
By stoichiometry the following mass quantities participate in the reaction:
- C: 1 mole* 12 g/mole= 12 g
- O₂: 1 mole* 32 g/mole= 32 g
- CO₂: 1 mole* 44 g/mole= 44 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
If 12 grams of C react, by stoichiometry 32 grams of O₂ react. But you have 40 grams of O₂. Since more mass of O₂ is available than is necessary to react with 12 grams of C, carbon C is the limiting reagent.
Then by stoichiometry of the reaction, you can see that 12 grams of C form 44 grams of CO₂.
<u><em>44 grams of CO₂ will be formed.</em></u>
Answer:
The answer is definitely D
Explanation:
2-7 days, but depends on the procedure
