Answer:- 1337 g
Solution:- For mathematical operations we use PEMDAS. P stands for parenthesis off, E stands for exponents, M stands for multiplication, D stands for division, A stands for addition and S stands for subtraction. All the mathematical operations are done in this sequence.
What we have given in the problem is, 1210.0 g + 157.22 g - 30. g
Here we have addition and subtraction. As per the law, we will do addition first. In addition and subtraction we go with least number of decimal places.
1210.0 has one decimal place where as 157.22 has two decimal places, since the first number has least decimal places(one decimal place), the answer should also have only one decimal place.
1210.0 g + 157.22 g = 1367.2 g
Now, we will do subtraction. 30. does not have any decimal place and so on subtraction the final answer must not have any decimal places.
1367.2 g - 30. g = 1337 g
So, the final answer is 1337 g.
Answer:
The moles of KClO3 = 0.052 moles
Explanation:
Step 1: Calculate the pressure of oxygen gas
The oxygen has a total pressure (including water vapour) of 760 mmHg
The pressure of Oxygen = (760 - 26) mmHg
= 734 mmHg of water vapor
Step 2: Calculate the no of moles of oxygen
Using Ideal gas equation
P V = n R T
P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas
V = 2 litres = 0.002 m3
R = gas constant = 8.31
T= 27oC = 300 K
Applying this equation P V = n R T
97,858.6 x 0.002 = n x 8.31 x 300
n = 0.0785 mol of Oxygen
From the balanced equation
2 KClO 3 ---- 2 KCl + 3 O 2
3 moles of oxygen is produced from 2 moles KClO3
so 0.0785 mole of oxygen will be produced from x
x = (0.0785 x 2 ) / 3
x = 0.052 moles of KClO3
Answer:
Sal, cobre, aluminio, anillo de oro puro Oxígeno ------ suspensión.
Cerveza, carbonato de sodio, oxígeno, carbono y helio ------ solución.
Explicación:
Sal, Cobre, Aluminio, Anillo de oro puro Oxígeno son los ejemplos de suspensión porque permanecen suspendidos en la solución mientras que por otro lado, Cerveza, Carbonato de sodio, Oxígeno, Carbono y helio son los ejemplos de solución porque formaron una mezcla homogénea en la que ambas soluciones no se pueden diferenciar entre sí pero en suspensión sí se pueden diferenciar.
A- Drilling through the Earth to reach areas is useful but expensive
