The answer to this question would be: Object B must become negatively charged.
An object with a positive charge will exert pulling force to object with a negative charge but will push an object with a positive charge. If object A and B brought close together and object A have a positive charge, object B must be turned into a negative charge.
Answer:
D. Flow separation is caused due to adverse pressure gradient in the flowing fluid.
Explanation:
Flow separation :
When adverse pressure gradient become dominate then phenomenon of flow separation occurs.In the other words when boundary layer is form against the adverse pressure then phenomenon of flow separation occurs.The adverse pressure means a opposing which act in the opposite to the direction of fluid flow.Due to flow separation eddy formation occurs and these eddy leads to increases the losses in the fluid flow.Due to flow separation fluid leaves the solid surface and form eddies.
So the answer is D.
Answer:
Explanation:
Given that,
At one instant,
Center of mass is at 2m
Xcm = 2m
And velocity =5•i m/s
One of the particle is at the origin
M1=? X1 =0
The other has a mass M2=0.1kg
And it is at rest at position X2= 8m
a. Center of mass is given as
Xcm = (M1•X1 + M2•X2) / (M1+M2)
2 = (M1×0 + 0.1×8) /(M1 + 0.1)
2 = (0+ 0.8) /(M1 + 0.1)
Cross multiply
2(M1+0.1) = 0.8
2M1 + 0.2 =0.8
2M1 = 0.8-0.2
2M1 = 0.6
M1 = 0.6/2
M1 = 0.3kg
b. Total momentum, this is an inelastic collision and it momentum after collision is given as
P= (M1+M2)V
P = (0.3+0.1)×5•i
P = 0.4 × 5•i
P = 2 •i kgm/s
c. Velocity of particle at origin
Using conversation of momentum
Momentum before collision is equal to momentum after collision
P(before) = M1 • V1 + M2 • V2
We are told that M2 is initially at rest, then, V2=0
So, P(before) = 0.3V1
We already got P(after) = 2 •i kgm/s in part b of the question
Then,
P(before) = P(after)
0.3V1 = 2 •i
V1 = 2/0.3 •i
V1 = 6 ⅔ •i m/s
V1 = 6.667 •i m/s
Plasma would be your answer. Plasma separates due to extremely high temperatures. I hope I could help!
