Answer:
0.06597
Step-by-step explanation:
Given that thirty-seven percent of the American population has blood type O+
Five Americans are tested for blood group.
Assuming these five Americans are not related, we can say that each person is independent of the other to have O+ blood group.
Also probability of any one having this blood group = p = 0.37
So X no of Americans out of five who were having this blood group is binomial with p =0.37 and n =5
Required probability
=The probability that at least four of the next five Americans tested will have blood type O+
= 
Answer:
- B) One solution
- The solution is (2, -2)
- The graph is below.
=========================================================
Explanation:
I used GeoGebra to graph the two lines. Desmos is another free tool you can use. There are other graphing calculators out there to choose from as well.
Once you have the two lines graphed, notice that they cross at (2, -2) which is where the solution is located. This point is on both lines, so it satisfies both equations simultaneously. There's only one such intersection point, so there's only one solution.
--------
To graph these equations by hand, plug in various x values to find corresponding y values. For instance, if you plugged in x = 0 into the first equation, then,
y = (-3/2)x+1
y = (-3/2)*0+1
y = 1
The point (0,1) is on the first line. The point (2,-2) is also on this line. Draw a straight line through the two points to finish that equation. The other equation is handled in a similar fashion.
Easy, just write out the multiple of the numbers.
4: 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60
7: 7,14,21,28,35,42,49,56,63,70
Etc.
But a few common multiples:
28,56,84,112,140
These are the first 5 common multiples of 4 and 7.
Daniel did. Happy Halloween can u mark me as brainliest and thanks. I neeed to rank up