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maksim [4K]
1 year ago
8

In spiral galaxies, the relationship between nuclear bulge and tightness of spiral arms seems to be that

Physics
1 answer:
Rus_ich [418]1 year ago
7 0

In spiral galaxies, the relationship between nuclear bulge and tightness of spiral arms seems to be that the larger the nuclear bulge of the galaxy, tighter the spiral arms are wound together.

What are spiral galaxies?

Spiral galaxies form a class of galaxy originally described by Edwin Hubble in his 1936 work The Realm of the Nebulae and, as such, form part of the Hubble sequence.

Most spiral galaxies consist of a flat, rotating disk containing stars, gas and dust, and a central concentration of stars known as the bulge. These are often surrounded by a much fainter halo of stars, many of which reside in globular clusters.

Spiral galaxies are named by their spiral structures that extend from the center into the galactic disc.

The spiral arms are sites of ongoing star formation and are brighter than the surrounding disc because of the young, hot OB stars that inhabit them.

Roughly two-thirds of all spirals are observed to have an additional component in the form of a bar-like structure, extending from the central bulge, at the ends of which the spiral arms begin.

The proportion of barred spirals relative to bar less spirals has likely changed over the history of the universe, with only about 10% containing bars about 8 billion years ago, to roughly a quarter 2.5 billion years ago, until present, where over two-thirds of the galaxies in the visible universe (Hubble volume) have bars.

To learn more about spiral galaxies: brainly.com/question/14243370

#SPJ4

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Answer:

\theta = 66.7 degree

Explanation:

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so we will have

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cos\theta - \mu sin\theta > 0

tan\theta = \frac{1}{\mu}

\theta = tan^{-1}\frac{1}{\mu}

\theta = tan^{-1}(\frac{1}{0.43})

\theta = 66.7 degree

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