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leonid [27]
3 years ago
6

According to the amortization table, Demarco and Tanya will pay a total of in interest over the life of their loan.

Engineering
2 answers:
Ymorist [56]3 years ago
8 0

Answer:

(Interest rate/number of payments)*$170000= interest for the first month.

Interest amounts for all the months of repayment plus $170000=Total loan cost

Explanation:

Interest is the amount you pay for taking a loan from a bank on top of the original amount borrowed.

Factors affecting how much interest is paid are; the principal amount, the loan terms, repayment schedule, the repayment amount and the rate of interest.

The interest paid=(rate of interest/number of payments to make)*principal amount borrowed.

You divide the interest with number of payments done in a year where monthly are divided by 12.Multiplying it by loan balance in the first month which is your principal amount gives the interest rate to pay for that month.

You new loan balance will be= Principal -(repayment-interest)

Do this for the period the loan should take.

Add all the interest amount to original borrowed amount to get total cost of the loan after the period of time.

algol133 years ago
6 0

Answer:

the answer for the first one is 104,854 and for the second one its 274,854

Explanation:

just did the assinment and got it right hope this helps  

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One kilogram of water fills a 150-L rigid container at an initial pressure of 2 MPa. The container is then cooled to 40∘C. Deter
lukranit [14]

The pressure of water is 7.3851 kPa

<u>Explanation:</u>

Given data,

V = 150×10^{-3} m^{3}

m = 1 Kg

P_{1} = 2 MPa

T_{2}  = 40°C

The waters specific volume is calculated:

v_{1} = V/m

Here, the waters specific volume at initial condition is v_{1}, the containers volume is V, waters mass is m.

v_{1} = 150×10^{-3} m^{3}/1

v_{1} = 0.15 m^{3}/ Kg

The temperature from super heated water tables used in interpolation method between the lower and upper limit for the specific volume corresponds 0.15 m^{3}/ Kg and 0.13 m^{3}/ Kg.

T_{1}= 350+(400-350) \frac{0.15-0.13}{0.1522-0.1386}

T_{1} = 395.17°C

Hence, the initial temperature is 395.17°C.

The volume is constant in the rigid container.

v_{2} = v_{1}= 0.15 m^{3}/ Kg

In saturated water labels for T_{2}  = 40°C.

v_{f} = 0.001008 m^{3}/ Kg

v_{g} = 19.515 m^{3}/ Kg

The final state is two phase region v_{f} < v_{2} < v_{g}.

In saturated water labels for T_{2}  = 40°C.

P_{2} = P_{Sat} = 7.3851 kPa

P_{2} = 7.3851 kPa

7 0
3 years ago
A solid cylinder of diameter 100 mm and height 50 mm is forged between two frictionless flat dies to a height of 25 mm. What is
coldgirl [10]

Answer:

d. 41.4

Explanation:

The initial diameter di = 100mm

The initial height hi {✓59m

Final height = 25 m

Final diameter = ?

Initial volume = after forging volume

D*(di)²*hi = D *(df)²*hf

D will cancel out from either sides of the equation

100² x 50 = df²x25

10000x2 = df²

20000 = df²

df = √20000

df = 141.42mm

Change in diameter = 141.42-100

= 41.42

The percentage change = 41.42/100*100

= 41.4%

The last option is the answer

4 0
3 years ago
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6 0
3 years ago
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Marshall's ruling in Marbury v. Madison is a testament to his strategic political skills for which of the following reasons? Sel
gladu [14]

Answer:

The following reason is letter D.

Explanation:

<em>Even though the real correct answer should be:  It did not immediately strenghten the Court's power in its relations with the President or Congress.</em>

6 0
4 years ago
What is tear test? What do we understand from this test? How?
Anvisha [2.4K]

Explanation:

The tear test determines the force required by a material to undergo complete failure when there is already a crack or tear present in it.

With this test we understand a material's resistance to failure when there is already a crack present.

The material which already has a crack is placed in a tensile testing or universal test machine. So, both sides of the material along the crack are pulled until material failure takes place.

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4 years ago
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