Answer:
2.08V/cm
Explanation:
Plot the points on a graph. Draw the line of best fit. Calculate the gradietn of line of best fit.
Attached is the graph plotted on excel.
The equation of the line is
Votlage= 2.08× distance + 0.276
Answer:
learn from their mistakes
Explanation:
and so u could do better next time
Answer:
The answer is option
C . the JFET has a PN junction
Explanation:
Not only is option C in the question a dissimilarity between the MOSFET and the JFET we can go on with some more dissimilarities.
1.MOSFET stands for Metal Oxide Silicon Field Effect Transistor or Metal Oxide Semiconductor Field Effect Transistor.
(JFET) stands for junction gate field-effect transistor (JFET)
2. JFET is a three-terminal semiconductor device, whereas MOFET a four-terminal semiconductor device.
3. In terms of areas of application of JFETs are used in low noise applications while MOSFETs, are used for high noise applications
Answer:
a. 9947 m
b. 99476 times
c. 2*10^11 molecules
Explanation:
a) To find the mean free path of the air molecules you use the following formula:

R: ideal gas constant = 8.3144 Pam^3/mol K
P: pressure = 1.5*10^{-6} Pa
T: temperature = 300K
N_A: Avogadros' constant = 2.022*10^{23}molecules/mol
d: diameter of the particle = 0.25nm=0.25*10^-9m
By replacing all these values you obtain:

b) If we assume that the molecule, at the average, is at the center of the chamber, the times the molecule will collide is:

c) By using the equation of the ideal gases you obtain:

Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem