I =p/4pir^2 solving for r
1 answer:
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The speed at which the arrow would be launched is 133.42 m/s
The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.
The equation for the work-energy theorem can be computed as:
where;
- Force (F) = 267 N
- distance Δx = 0.60 m
- mass (m) = 18 g
- speed (v) = ???
From the above equation, let make speed(v) the subject of the formula:
∴
v = 133.42 m/s
Learn more about the work-energy theorem here:
Answer:
V = 1.1 m/s
Explanation:
given,
mass of railroad car 1 , m = 30,000. kg
travelling at the speed , u = 2.2 m/s
mass of car 2, M = 30,000. kg
initial speed, u' = 0 m/s
final speed of the car after collision, V = ?
using conservation of momentum
m u + M u' = (M+m)V
30000 x 2.2 + 0 = (30000 + 30000) V
60000 V = 66000
V = 1.1 m/s
he velocity of the two cars is equal to V = 1.1 m/s