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GenaCL600 [577]
3 years ago
11

A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a

power of 10. All numbers in scientific notation have the following form.
A✕10^n
The mass of the Sun is 1,990,000,000,000,000,000,000,000,000,000 kg. Express the mass in kg using scientific notation. (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e+2 for 120. WebAssign allows you to enter answers using scientific notation. For example, a number in scientific notation such as 1.32 104 would need to be entered as 1.32e4. The system requires that you do not use spaces. Enter your answer to two decimal places.)Â
____________kg
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

Mass = 1.99 * 10^{30} kg

Explanation:

Given

Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg

Required

Rewrite using scientific notation

The format of a number in scientific notation is

Digit = a * 10^n

Where 1 \geq\ a\geq\ 10

So the given parameter can be rewritten as

Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg

Express as a power of 10

Mass = 1.99 * 10^{30} kg

Hence, the equivalent of the mass of the sun in scientific notation is:

Mass = 1.99 * 10^{30} kg

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A plane comes in for a landing at a velocity of 80 meters per second west. As it touches down, it decelerates at a constant rate
azamat

Answer:

Answer D : about 1067 meters

Explanation:

There are two steps to this problem:

1) First find the time it takes the plane to stop using the equation for the acceleration:

a=\frac{Vf-Vi}{t}

Where Vf is the final velocity of the plane (in our case: zero )

Vi is the initial velocity of the plane (in our case: 80 m/s)

a is the acceleration (in our case -3 m/s^2 - notice negative value because the velocity is decreasing)

a=\frac{Vf-Vi}{t}\\-3=\frac{0-80}{t}\\t=\frac{-80}{-3} = \frac{80}{3}

with units corresponding to seconds given the quantities involved in the calculation.

2) Second knowing the time it took the plane to stop, now use that time in the equation for the distance traveled under accelerated motion:

Xf-Xi=Vi*t+\frac{1}{2} a t^{2} \\Xf-Xi= 80 (\frac{80}{3}) +\frac{1}{2} (-3) (\frac{80}{3}) ^{2}=1066.666666...

Where the answer results in units of meters given the quantities used in the calculation.

We round this to 1067 meters

7 0
3 years ago
What is the function of a switch? pls HELPPPPPP TYSMMMMM <3​
lesya [120]

Answer:

Connect multiple hosts: Normally, a switch provides a large number of ports for cable connections, allowing for star topology routing. It is usually used to connect multiple PCs to the network. Forwards a message to a specific host: Like a bridge, a switch uses the same forwarding or filtering logic on each port. When any host on the network or a switch sends a message to another host on the same network or the same switch, the switch receives and decodes the frames to read the physical (MAC) address portion of the message. Manage traffic: A switch in networking can manage traffic either coming into or exiting the network and can connect devices like computers and access points with ease. Keep electrical signal undistorted: When a switch forwards a frame, it regenerates an undistorted square electrical signal. Increase LAN bandwidth: A switch divides a LAN into multiple collision domains with independent broadband, thus greatly increasing the bandwidth of the LAN.

Explanation:

8 0
3 years ago
Read 2 more answers
A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00s. How far does the car travel during those 5.00
Doss [256]

Answer:

d = 105 m

Explanation:

Speed of a car, v = 21 m/s

We need to find the distance traveled by the dar during those 5 s before it stops. Let the distance is d. It can be calculated as :

d = v × t

d = 21 m/s × 5 s

d = 105 m

So, it will cover 105 m before it stops.

5 0
3 years ago
3 PHYSICAL SCIENCE: In order to figure out what is in a sealed box, you perform some tests. The box seems heavy for its size and
rjkz [21]
Some sort of magnetic metal

Metals are heavier per cubic unit than other materials such as air or water, and also are much more magnetic than other materials
7 0
4 years ago
1. You place an object 63 cm in front of a converging lens, with a 40 cm focal length.
NikAS [45]

Answer:

1.

109.6 cm ,  - 1.74 , real

2.

1.5

Explanation:

1.

d₀ = object distance = 63 cm

f = focal length of the lens = 40 cm

d = image distance = ?

using the lens equation

\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}

\frac{1}{40} = \frac{1}{63} + \frac{1}{d}

d = 109.6 cm

magnification is given as

m = \frac{-d}{d_{o}}

m = \frac{-109.6}{63}

m = - 1.74

The image is real

2

d₀ = object distance = a

d = image distance = - (a + 5)

f = focal length of lens = 30 cm

using the lens equation

\frac{1}{f} = \frac{1}{d_{o}} + \frac{1}{d}

\frac{1}{30} = \frac{1}{a} + \frac{1}{- (a + 5)}

a = 10

magnification is given as

m = \frac{-d}{d_{o}}

m = \frac{- (- (a +5))}{a}

m = \frac{(5 + 10)}{10}

m = 1.5

6 0
3 years ago
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