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GenaCL600 [577]
3 years ago
11

A number is written in scientific notation when it is the product of a number less than 10 but greater than or equal to 1 and a

power of 10. All numbers in scientific notation have the following form.
A✕10^n
The mass of the Sun is 1,990,000,000,000,000,000,000,000,000,000 kg. Express the mass in kg using scientific notation. (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e+2 for 120. WebAssign allows you to enter answers using scientific notation. For example, a number in scientific notation such as 1.32 104 would need to be entered as 1.32e4. The system requires that you do not use spaces. Enter your answer to two decimal places.)Â
____________kg
Physics
1 answer:
Bess [88]3 years ago
7 0

Answer:

Mass = 1.99 * 10^{30} kg

Explanation:

Given

Mass = 1,990,000,000,000,000,000,000,000,000,000\ kg

Required

Rewrite using scientific notation

The format of a number in scientific notation is

Digit = a * 10^n

Where 1 \geq\ a\geq\ 10

So the given parameter can be rewritten as

Mass = 1.99 * 1,000,000,000,000,000,000,000,000,000,000\ kg

Express as a power of 10

Mass = 1.99 * 10^{30} kg

Hence, the equivalent of the mass of the sun in scientific notation is:

Mass = 1.99 * 10^{30} kg

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No, neutrons have about the same mass as a proton, but both have more mass than electrons.

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If I push on the wall with 75 Newtons of force, the wall will push back with __
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Answer: 0

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75 newtons will push back canceling it out make it 0

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Baseball Digest is but one of several publications on the sport of baseball. True or False?
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Answertrue

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Read 2 more answers
Two uncharged metal spheres, spaced 25.0 cm apart, have a capacitance of 26.0 pF. How much work would it take to move 12.0 nC of
viktelen [127]

Answer:

W=2.76\times 10^{-6}\ J

Explanation:

Given that,

The distance between two spheres, r = 25 cm = 0.25 m

The capacitance, C = 26 pF = 26×10⁻¹² F

Charge, Q = 12 nC = 12 × 10⁻⁹ C

We need to find the work done in moving the charge. We know that, work done is given by :

U=\dfrac{Q^2}{2C}

Put all the values,

U=\dfrac{(12\times 10^{-9})^2}{2\times 26\times 10^{-12}}\\\\U=2.76\times 10^{-6}\ J

So, the work done is 2.76\times 10^{-6}\ J.

8 0
3 years ago
The drawing shows a large cube (mass = 28.6 kg) being accelerated across a horizontal frictionless surface by a horizontal force
MrRissso [65]

Answer:

P= 454.11 N

Explanation:

Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).

P= (M+m)*a\\a = \frac{P}{28.6 +4.3}\\a = \frac{P}{32.9}

The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

F = m * a*\mu \\F= 4.3*0.710*\frac{P}{32.9}\\F=3.053*\frac{P}{32.9}

In order for the small cube to not slide down, the friction force must equal the weight of the small cube:

3.053*\frac{P}{32.9} = 4.3 * g\\\\P = \frac{4.3*9.8*32.9}{3.053} \\P= 454.11 N

The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N

8 0
3 years ago
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