Answer:
A) hydrostatic force on top of cube = 882.9N
B) hydrostatic force on sides of cube = 0N
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>
Explanation:
<h3>Greetings !</h3>
Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3>
<u>Given</u><u> </u><u>values</u></h3>
- m= 18.02597
- c=3.00×10⁸ms¯¹
<h3><u>required </u><u>value</u></h3>
<h3><u>Solution:</u></h3>
- Eb=(Δm)c²
- Eb=(18.02597)*(3.00*10⁸ms¯¹
- Eb=5.407791*10⁹J
Answer:
pressure, stress pascal N/m2
energy, work, quantity of heat joule N·m
power, radiant flux watt J/s
electric charge, quantity of electricity coulomb -
Answer: 250n
Explanation:
The formula for gravitational force is: F = (gMm)/r^2
There are two factors at play here:
1) The mass of the planet 'M'
2) The radius 'r'
We can ignore the small M and the g, they are constants that do not alter the outcome of this question.
You can see that both M and r are double that of earth. So lets say earth has M=1 and r=1. Then, new planet would have M=2 and r=2. Let's sub these two sets into the equation:
Earth. F = M/r^2 = 1/1
New planet. F = M/r^2 = 2/4 = 1/2
So you can see that the force on the new planet is half of that felt on Earth.
The question tells us that the force on earth is 500n for this person, so then on the new planet it would be half! So, 250n!
Answer:Lenz's Law of Electromagnetic Induction. ... This voltage is called an induced emf as it has been induced into the conductor by a changing magnetic field due to electromagnetic induction with the negative sign in Faraday's law telling us the direction of the induced current (or polarity of the induced emf).
Explanation:
