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2 years ago

A............... pulley helps us by changing the direction of the applied effort

Physics

2 answers:

DerKrebs [107]2 years ago

8 0

Explanation:

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garik1379 [7]2 years ago

8 0

Answer/Explanation:

True

A fixed pulley changes the direction of the force you exert by pulling, so you can pull down to move an object up. In this fixed pulley system, you pull down on one side of the rope and the other side goes up. You use the same amount of force to pull down as you would to lift the toy yourself.

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Consider a person sliding down a water slide at constant velocity. what are the forces acting on the person as they slide? are t

Andru [333]

Explanation :

When a person is sliding with constant velocity, the forces that are acting on him are :

(1) Weight, W = mg where g is acceleration due to gravity.

(2) Friction forces acting opposite to the direction of motion.

(3) Normal force.

The forces acting on the person is balanced because the person is sliding with constant velocity.

From figure it is clear that, friction force is balanced by $w\ sin\theta$ and normal is balanced by $w\ cos\theta$ .

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2 years ago

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What are the types of realistic fiction?.

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The types of realistic fiction: are historical and contemporary fiction.

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1 year ago

1.The putt shot is used for hitting the golf ball off of the golf tee.

MArishka [77]

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1.True 2.

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2 years ago

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A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13k

Veronika [31]

Answer:

$14.98\ \text{kg m/s}$

$45.26^{\circ}$

Explanation:

$P_1$ = Initial momentum of the pin = 13 kg m/s

$P_i$ = Initial momentum of the ball = 18 kg m/s

$P_2$ = Momentum of the ball after hit

$55^{\circ}$ = Angle ball makes with the horizontal after hitting the pin

$\theta$ = Angle the pin makes with the horizotal after getting hit by the ball

Momentum in the x direction

$P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}$

Momentum in the y direction

$P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}$

$(P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}$

The pin's resultant velocity is $14.98\ \text{kg m/s}$

$P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}$

The pin's resultant direction is $45.26^{\circ}$ below the horizontal or to the right.

4 0

2 years ago

A 2-kg box sits on a horizontal table. the force of friction between the box and the table is 10 n. the box is pushed to the rig

dangina [55]

By Newton's 2nd law of motion, F = ma, where F is force, m is mass, and a is acceleration.

Rearranging this equation to find acceleration would give us:
a = F/m

The horizontal force to the right is 10N, because the box is pushed to the right with a force of 20N, and the friction force of 10N opposes that, so:
20N - 10N = 10N

The mass is 2kg.

Putting these values into the equation gives us:
a = F/m
= 10/2
= 5ms^-2

The acceleration of the box is 5ms^-2

6 0

3 years ago

A............... pulley helps us by changing the direction of the applied effort​

A............... pulley helps us by changing the direction of the applied effort