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attashe74 [19]
2 years ago
12

How much faster does ethane (C2H6) gas travel compared to chlorine gas?

Chemistry
1 answer:
zimovet [89]2 years ago
5 0

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ =  70.91 g/mol

M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

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kow [346]

The mass of the Pbl2 : 1308.87

<h3>Further explanation</h3>

Given

18.2 mL of a 0.156 M Pb(NO3)2

26.2 mL of a 0.274 M KI

Reaction

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Required

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Solution

mol Pb(NO3)2 = 18.2 x 0.156 = 2.8392 mlmol

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Limiting reactant Pb(NO3)2(smaller ratio of mol : reaction coeffiecient)

mol Pbl2 based on limiting reactant (Pb(NO3)2)

From equation, mol ratio of Pb(NO3)2 : Pbl2 = 1 : 1, so mol Pbl2=mol Pb(NO3)2=2.8392

Mass Pb(NO3)2 :

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What is the value of for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 kj/mol
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<h3>What is an aqueous reaction in equilibrium?</h3>

When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.

δG = − R T ln

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substituting the value in the equation.

20. 46 kj/mol = 8.313 × 24.4 in celcius × K

K =  8.313 × 24.4 in celcius / 20. 46 kj/mo

k = 9.91 mol .

Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium

Learn more about the aqueous reaction in  equilibrium, here:

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