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Ivenika [448]
3 years ago
12

25 points! Please someone help me, this seems like a pretty easy question but I can’t seem to get it right, please list the give

ns and make some sort of diagram so I can understand. I will give brainliest !!!!!
1. Draw the diagram

2. List the Givens

3. Select the correct equation to solve for and manipulate the equation

4. Substitute the given values


A ball is thrown horizontally from the roof of a building 60 m tall with a speed of

6.9 m/s.

a.How much later does the ball hit the ground?

b. How far from the building will it land?

c. What is the velocity of the ball just before it hits the ground?
Physics
1 answer:
elixir [45]3 years ago
4 0

Answer:

1 my brother say that

Explanation:

i know my brother said it

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Which of the following is most likely not a case of uniform circular motion
Ivan

Answer:

Motion of a racing car on a circular track

Explanation:

Uniform circular motion means the motion of the object is in a circle with a CONSTANT SPEED.

The racing car will accelerate during its motion. Hence, it is not a uniform circular motion.

7 0
3 years ago
What is the ideal banking angle for a gentle turn of 1.20-km radius on a highway with a 105 km/h speed limit (about 65 mi/h), as
Mnenie [13.5K]

Answer:

4.14°

Explanation:

given:

r = 1.2 km

v = 105 km/h

1) <em>convert your given </em>

a) r = 1.2 km to m = 1200m

b) v = 105 km/h  to m/s = 29.2 m/s

2) <em>plug into your ideal banking angle equation</em>

tan^-1(\frac{v^2}{rg}) = \frac{29.2^2}{(1200)(9.8)} = 4.14°

8 0
2 years ago
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
3 years ago
When an object moved in a circle ___ acts to accelerate the object toward the center of that cirlce
Irina18 [472]
Centripital acceleration. When an object moves in a circle, centripital acceleration acts to accelerate the object towards the center of that circle
7 0
3 years ago
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A vector starts at the point (0, 0) and ends at (3, 1). What is the magnitude and direction of the displacement?
Sindrei [870]

Answer:

tbh vector does not have any direction at all the answer is 0

6 0
3 years ago
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