Chemistry => Stoichiometry => Limiting reactant
The maximum number of molecules that can be formed will depend on the limiting reactant. The limiting reactant corresponds to the reactant that produces the least amount of product, or in other words, the one that is completely consumed in the reaction.
To find the limiting reactant we are going to divide the moles of each reactant by the stoichiometric coefficients of the balanced equation, the reactant with the lowest ratio will be the limiting reactant.
The balanced equation for this reaction will be:
We have, according to the image the following number of molecules:
Xe=2molecules
F2=4molecules
The limiting reactant will be:
Both reactants are limiting reactants. We can take any reactant and we will have the same number of molecules of XeF4 formed. The ratio Xe to XeF4 is 1/1, so the molecules of XeF4 that can be formed will be:
Answer: 2 XeF4 molecules
The molecular formula is C₄H₈O.
We must <em>calculate the masses</em> of C, H, and O from the masses given.
Mass of C = 17.873 mg CO₂ × (12.01 mg C/44.01 mg CO₂) = 4.8774 mg C
Mass of H = 7.316 mg H₂O × (2.016 mg H/18.02 mg H₂O) = 0.818 48 mg H
Mass of O = Mass of compound - Mass of C - Mass of H
= (7.321 – 4.8774 – 0.818 48) mg = 1.6251 mg
Now, we must convert these <em>masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u> </u><em><u>m</u></em><u>/mg </u> <em><u>n</u></em><u>/mmol</u> <u> Ratio </u> <u>Integers</u>
C 4.877 4 0.406 11 3.9984 4
H 0.818 48 0.811 99 7.9944 8
O 1.625 1 0.101 57 1 1
The empirical formula is C₄H₈O.
I believe the answer is false
Mol (n) = 29.0
molar mass (M) Na = 23 g/mol
mass (m) = ?
m = nxM
m = 29.0x23
m = 667 g
mol (n) = 29.0
molar mass (M) Cl = 35.5 g/mol
mass (m) = ?
m = nxM
m = 29.0x35.5
m = 1029.5 g