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3 years ago

Glycerine is known as a negative catalyst.why?

Chemistry

1 answer:

ioda3 years ago

6 0

Answer:

The presence of 1-2% ethanol as catalyst, suppresses the oxidation of chloroform with oxygen to give a poisonous gas called phosgene. ... Here glycerol acts as negative catalyst. Criteria or characteristics of catalysts. i. The mass and chemical composition of catalyst should remain unchanged at the end of the reaction.

Explanation:

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ivanzaharov [21]

<u>Answer:</u> The mass of second isotope of indium is 114.904 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

<u>For isotope 1:</u>

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

<u>For isotope 2:</u>

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

Hence, the mass of second isotope of indium is 114.904 amu

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3 years ago

When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the

Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

$\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}$

For 1000 C, W = x grams

$\tt x=\dfrac{1000.e}{96500}=0.0104e$

For 5x grams :

$\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C$

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3 years ago

Glycerine is known as a negative catalyst.why?​

Glycerine is known as a negative catalyst.why?