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goblinko [34]
3 years ago
11

Show how the total charge sodium oxide is zero

Chemistry
1 answer:
coldgirl [10]3 years ago
6 0
First, the symbol for sodium oxide is Na₂O

Each Na (sodium) has a charge of 1+, and each O has a charge of 2-  :

Na₂¹⁺O²⁻

There are two Na's, however, and each one is 1+, however, so the Na₂ has a total charge of 2+.  Because of this, the 2+ from the 2 Na's and the 2- from the O cancel each other out to make 0.
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How many total moles of ions are released when the following sample dissolves completely in water?
pogonyaev

Answer:

                      8.55 × 10²⁴ Ions

Explanation:

                    Ammonium Chloride is an ionic compound which contains a monatomic anion (Cl⁻ ; Chloride) and a polyatomic cation (NH₄⁺ ; Ammonium).

Hence, when added in water Ammonium Chloride ionizes as;

                                      NH₄Cl   →    NH₄⁺  +  Cl⁻

Hence, we can say that it produces two ions when dissolved in water.

Also,

We know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of ions  contained by 7.1 moles of NH₄Cl, we will use following relation to first calculate the number of molecules as;

          Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Molecules,

          Number of Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting values,

          Number of Molecules  =  7.1 mol × 6.022 × 10²³

          Number of Molecules  =  4.27 × 10²⁴ Molecules

So,

As,

                         1 Molecule of NH₄Cl contained  =  2 Ions

So,

              4.27 × 10²⁴ Molecules of NH₄Cl will contain  =  X ions

Solving for X,

                     X =  2 Ions × 4.27 × 10²⁴ Molecules / 1 Molecule

                    X =  8.55 × 10²⁴ Ions

8 0
3 years ago
How many atoms of S are there in the reactants?<br> Sg + F2 ---&gt; SFO
Alex Ar [27]

Answer:

One atom

Explanation:

4 0
3 years ago
Who is good with science?
MrMuchimi
I can help with science.
7 0
3 years ago
GIVE ME ANSWERS
Shalnov [3]

Answer:

uh.. How many do you want done??

Explanation:

6 0
3 years ago
Read 2 more answers
the standard change in Gibbs free energy is Δ????°′=7.53 kJ/molΔG°′=7.53 kJ/mol . Calculate Δ????ΔG for this reaction at 298 K29
Vera_Pavlovna [14]

Answer:

ΔG = 16.218 KJ/mol

Explanation:

  • dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
  • ΔG = ΔG° - RT Ln Q

∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol

∴  R = 8.314 J/K.mol

∴ T = 298 K

∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]

⇒ Q = 0.00300 / 0.100 = 0.03

⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))

⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )

5 0
3 years ago
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