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vovangra [49]
3 years ago
9

Which one is the right one dont mine the one i put that one is wrong

Chemistry
1 answer:
Degger [83]3 years ago
7 0

Answer: The answer is B

Explanation:

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Question 3 help me asap please
e-lub [12.9K]

Its chemical formula H2O, indicates that each of its molecules contains one oxygen and two hydrogen atoms, connected by covalent bonds. The hydrogen atoms are attached to the oxygen atom at an angle of 104.45°. "Water" is the name of the liquid state of H2O at standard conditions for temperature and pressure.

5 0
3 years ago
Which diagram represents this molecule
Rudik [331]

Answer:

I think it is C

Explanation:

Hope this helps!! :)

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5 0
3 years ago
The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J
Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

<em>A = 1,13x10¹⁰</em>

<em></em>

I hope it helps!

6 0
3 years ago
Which of the following is not a step in balancing redox reactions in acidic solution, using the half-reaction method?
schepotkina [342]
B <span>Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction 
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7 0
3 years ago
Read 2 more answers
If δh = -70.0 kj and δs = -0.500 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature. exp
Nina [5.8K]
Answer is: temperature must be less than 140 K.
Gibbs free energy (G) determines if reaction will proceed spontaneously. <span>If the value of G is a negative, the reaction is spontaneous. <span>ΔG = ΔH - T·ΔS.
</span></span>ΔH = -70.00 kJ.
ΔS = -0.500 kJ/K.
-70 kJ = T · (-0.5 kJ/K).
T = -70.00 kJ ÷ (-0.500 kJ/K).
T = 140 K. 
6 0
3 years ago
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