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nikdorinn [45]
3 years ago
10

The cost of membership in the school kayaking club is a $10.00 fee and $3.00

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

igwif

Step-by-step explanation:

392e6×0273=2048

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16
Tanya [424]

Answer:

2.50

Step-by-step explanation:

Given

(x_1,y_1) = (-1,0.8)

(x_2,y_2) = (0,2)

(x_3,y_3) = (1,5)

(x_4,y_4) = (2,12.5)

Required

The rate of change (b)

The above graph is represented as:

y = ab^x

For: (x_2,y_2) = (0,2);

We have:

y = ab^x

2 = a * b^0

2 = a *1

2 = a

a = 2

For (x_3,y_3) = (1,5),

We have:

y = ab^x

5 = a * b^1

5 = a * b

Substitute a = 2

5 = 2 * b

Divide by 2

2.5 = b

b = 2.5

<em>Hence, the rate of change is 2.50</em>

7 0
3 years ago
Maria has three red dresses, 2 white dresses, and one blue dress . What is the probability she will wear a blue dress at her par
dedylja [7]

Answer:

1/6

Step-by-step explanation:

there are 6 dresses altogether and 1 blue dress.

8 0
3 years ago
Read 2 more answers
Using the technique in the model above, find the missing sides in this 30°-60°-90° right triangle.
ale4655 [162]
Umm..... according to what I know      <span> </span><span>The ratio of the sides of a 30°-60°-90° triangle are:
short leg : long leg : hypotenuse
1 : √3 : 2
</span><span> if the short leg is 7, the long leg is √3 times that:
Answer:
7√3 ≈ 12.12 inches  </span>
8 0
3 years ago
Read 2 more answers
Will mark brainliest! Questions are in the picture!
alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the <u>perimeter </u>to the nearest tenth.

As we know that the area of triangle is ,

\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)

Substituting the respective values,

\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0

On using the <u>Quadratic</u><u> formula</u> , we have;

\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}

On simplifying above , we will get ,

\rm\longrightarrow x = 6.802,-9.802

Since sides can't be negative, therefore,

\rm\longrightarrow\underline{\underline{ x =6.802}}

Therefore ,

  • \rm\longrightarrow Base = 3x =3(6.802)in = 20.406\ in\\
  • \rm\longrightarrow Height = x +3=6.802+3=9.802\ in

Next let's find out the <u>hypotenuse </u>using Pythagoras theorem, as ;

\rm\longrightarrow h=\sqrt{ b^2+p^2}\\

\rm\longrightarrow h =\sqrt{ (20.406)^2+(9.802)^2}\\

\rm\longrightarrow h =\sqrt{416.40+96.07}\\

\rm\longrightarrow h = 22.63\ in

Now we may find perimeter as ,

\rm\longrightarrow P = p + b + h \\

\rm\longrightarrow P = (22.63 + 9.802 + 20.406)in.

\\\rm\longrightarrow P = 52.89 \ in.\\

\rm\longrightarrow \underline{\underline{ Perimeter = 52.9\ in .}}

8 0
3 years ago
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y
Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
5 0
3 years ago
Read 2 more answers
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