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zubka84 [21]
3 years ago
12

An aluminum ion has 13 protons, 14 neutrons, and 10 electrons. What is the charge of the aluminum ion?

Chemistry
1 answer:
Kipish [7]3 years ago
3 0

Answer:

+3

Explanation:

-10 + 13 = +3

-10 IS THE NUMBER OF ELECTRONS

13 IS THE NUMBER OF PROTONS

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When the pressure on 2.5 liters of oxygen is decreased from 2.0 atm to 1.0 atm, the volume of the gas
uranmaximum [27]

Answer:

volume of the gas is 5.0L

Explanation:

Using Boyle's law that state the pressure of a gas is inversely proportional to volume of it occupies when temperature is constant, it is possible to write:

P₁V₁ = P₂V₂

<em>Where P is pressure, V is volume and 1 and 2 are initial and final states.</em>

<em />

If initial volume is 2.5L, initial pressure is 2.0atm and 1.0atm is final pressure, final volume is:

2.0atm*2.5L = 1atm V₂

5.0L = V₂

Thus, <em>volume of the gas is 5.0L</em>.

5 0
3 years ago
Should the density of a metal depend on its volume?
jekas [21]

Answer:

Density is the ratio of the mass of an object to its volume. Density is an intensive property, meaning that it does not depend on the amount of material present in the sample. ... Since a cubic centimeter is equal to a milliliter, density units can also be expressed as g/mL.

Explanation:

6 0
3 years ago
How many moles are in 6.80 x 10^23 atoms <br> of gold, Au?
frosja888 [35]

Answer:

1.13 moles Au

Explanation:

Moles Au = 6.80x10²³atoms / 6.023x10²³atoms/mole = 1.13 moles Au

8 0
3 years ago
What is the density of a gas with a volume of 5.6 FL oz. and a mass of 37 grams?
Assoli18 [71]

Answer:

6.60

Explanation:

4 0
3 years ago
Read 2 more answers
Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth miles. Such massive ships require a dista
uranmaximum [27]

Answer:

Acceleration = (change in speed) / (time for the change)

Change in speed= (0 - 26 km/hr) = -26 km/hr

(-26 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) = -7.222 m/sec

Average acceleration = (-7.222 m/s) / (22 min x 60sec/min) = -0.00547 m/sec²

Average speed during the stopping maneuver =

              (1/2) (start speed + end speed) = 13 km/hr = 3.6111 m/sec

Explanation:

4 0
3 years ago
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