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zubka84 [21]
3 years ago
12

An aluminum ion has 13 protons, 14 neutrons, and 10 electrons. What is the charge of the aluminum ion?

Chemistry
1 answer:
Kipish [7]3 years ago
3 0

Answer:

+3

Explanation:

-10 + 13 = +3

-10 IS THE NUMBER OF ELECTRONS

13 IS THE NUMBER OF PROTONS

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At sea level, a kilogram welghs approximately<br> 2 pounds<br> 10 pounds<br> 5 pounds<br> 1 pound
Vedmedyk [2.9K]

Answer:

1 kilogram weight at sea level would be the equivalent of  2 pounds.

Explanation:

5 0
3 years ago
Calculate ΔH∘f for NO(g) at 435 K, assuming that the heat capacities of reactants and products are constant over the temperature
weeeeeb [17]

Answer:

91383 J

Explanation:

The equation of the reaction can be represented as:

\frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}     ------>NO_{(g)}

Given that:

The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.

The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

where:

\delta H^0__{R} = enthalpy of reaction

{\delta C_p(T')} = the difference in the heat capacities of the products and the reactants.

∴

\delta H^0__{R,435K} = \delta H^0__{R,298.15K} + \int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'

= 1(91300 J.mol^{-1} ) +\int\limits^{435}_{298.15} [{(29.86)-\frac{1}{2}(29.38)-\frac{1}{2}29.13}]J.K^{-1}.mol^{-1} \, dT'

= 91300 J + (0.605 J.K⁻¹)(435-298.15)K

= 91382.79 J

\delta H^0__{R,435K} ≅ 91383 J

6 0
4 years ago
a substance has a definite volume but no definite shape ? state whether this substance is a solid , a liquid , or a gas.​
DerKrebs [107]

Answer:

A liquid

Explanation:

This is the answer!! Hope this helps.

4 0
3 years ago
Chemistry question please help!!
LiRa [457]
Answer: It’s the first one
8 0
3 years ago
Are the base pairs always the same?
Monica [59]
No  because they can be seperated differently

6 0
3 years ago
Read 2 more answers
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