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Umnica [9.8K]
3 years ago
14

A ball is thrown into the air with a velocity of 102 feet per second

Mathematics
1 answer:
valina [46]3 years ago
7 0

Answer:

and what are you needin to find out

Step-by-step explanation:

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Help me now !!!!!<br> help i need help
iren2701 [21]

cylinder:

V = πr²h

V = 3.14(2)² * 3

V = 3.14(4) * 3

V = 3.14(12)

V = 37.7m³

rectangular prism:

V = lwh

V = (2.4)(9)(5)

V = 108m³

the entirety of the sculpture:

V = volume of cylinder + volume of rectangular prism

V = 37.7 + 108

<u>V = 145.7m³</u>

4 0
2 years ago
The Gallup Poll uses a procedure called random digit dialing, which creates phone numbers based on a list of all area codes in A
kondaur [170]
Random digit dialing<span> (RDD) is a method for selecting people for involvement in telephone statistical surveys by generating telephone numbers at </span>random<span>. </span>Random digit dialing<span> has the advantage that it includes unlisted numbers that would be missed if the numbers were selected from a phone book.</span>
5 0
3 years ago
Read 2 more answers
For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
Pani-rosa [81]

Answer:

x = 14.25

Step-by-step explanation:

Start with a^2 + b^2 = c^2

a = 11

b = x

c = 18

plug in and solve

11^2 + x^2 = 18^2

121 + x^2 = 324 - Simplify

x^2 = 203 - subtract 121 from both sides

x = 14.247 rounds to 14.25 - square root on both sides

7 0
3 years ago
Please help i will mark branliest
mafiozo [28]

Answer:

The answer is d

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The population mean annual salary for environmental compliance specialists is about ​$62,000. A random sample of 32 specialists
lakkis [162]

Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about ​$62,000.

i.e. \mu=62000  

Sample size : n= 32

\sigma=6200

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 59000 will be :

z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than ​$59,000 :-

P(z

Hence, the probability that the mean salary of the sample is less than ​$59,000= 0.002718

3 0
3 years ago
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