2 years ago

Using the Periodic Table, Which of the following has the largest atomic radius/size?

Chemistry

1 answer:

soldier1979 [14.2K]2 years ago

6 0

Answer:

vp jokhimon vf dpp gl fl vk hggjuvg7vvohohohohojj

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Explanation:

From the question we are told that:

Mass of mixture $m=3.455g$

Mass of Barium $m_b=0.2815g$

Equation of Reaction is given as

$Ba2+ + H2SO4 => BaSO4 + 2 H+$

Generally the equation for Moles of Barium is mathematically given by

Since

$Moles of Ba^{2+} = Moles of BaSO_4$

Therefore

$Moles of Ba^{2+} = \frac{mass}{molar mass of BaSO4}$

$Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol$

Generally the equation for Mass of Barium is mathematically given by

$Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}$

$Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g$

Therefore

$Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%$

$Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%$

$Ba\ percentage\ in\ Mass=4.8\%$

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