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guajiro [1.7K]
3 years ago
6

How do you know if a chemical change has taken place?

Chemistry
1 answer:
9966 [12]3 years ago
6 0
There are a few ways to tell if a reaction has taken place, these include temperature change, color change, formation of a precipitate, bubbling, and even odors. These all indicate that a chemical change has taken place.
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It is desired to make 1.00 liter of 6.00 M nitric acid from concentrated 16.00 M HNO3.A) How many moles of nitric acid are in 1.
natima [27]

Answer:

A) 6.00 mol.

B) 0.375 L or 375 mL

C) 6.00 M

Explanation:

Hello,

A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:

n=M*V=1.00L*6.00mol/L=6.00mol

B) In this case, from the stock solution, the required volume is:

V=\frac{6.00mol}{16.00mol/L}=0.375L

C) In this case, we apply the following formula for dilution process:

M_1V_1=M_2V_2

Thus, solving for the final molarity, we obtain:

M_2=\frac{M_1V_1}{V_2}=\frac{16.00M*0.375L}{1.00L}\\  \\M_2=6.00M

Regards.

5 0
2 years ago
Somebody tell me- why do cows go Moo?
m_a_m_a [10]

Answer:

To communicate with each other

Explanation:

Cows use sound (mooing) to communicate with each other and their environment. Cows are herd animals and have complex social structures. Mooing is one way that they interact and how they express their emotions

5 0
2 years ago
Read 2 more answers
What is the noble Gas notation for Bromine (Br)?
PSYCHO15rus [73]
3d10 4s2 4p5. I think
6 0
2 years ago
A4 kg object is being pulled to the east by a 6 N force. What is the object's<br> acceleration?
Dahasolnce [82]

1.5 ms⁻²

Explanation:

We understand that Force is also given as mass * acceleration;

F = Ma

If force is 6N and the mass is 4kg of the object, the a can be evaluated as follows;

6 = 4a

6/4 = a

1.5 = a

= 1.5m/s²

4 0
3 years ago
Sulfur dioxide has a vapor pressure of 462.7 mm Hg at –21.0 °C and a vapor pressure of 140.5 mm Hg at –44.0 °C. What is the enth
stealth61 [152]

Answer : The value of \Delta H_{vap} is 28.97 kJ/mol

Explanation :

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature -21.0^oC = 462.7 mmHg

P_2 = vapor pressure at temperature -44.0^oC = 140.5 mmHg

\Delta H_{vap} = Enthalpy of vaporization = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = -21.0^oC=[-21.0+273]K=252K

T_2 = final temperature = 45^oC=[-41.0+273]K=232K

Putting values in above equation, we get:

\ln(\frac{140.5mmHg}{462.7mmHg})=\frac{\Delta H_{vap}}{8.314J/mol.K}[\frac{1}{252}-\frac{1}{232}]\\\\\Delta H_{vap}=28966.6J/mol=28.97kJ/mol

Therefore, the value of \Delta H_{vap} is 28.97 kJ/mol

4 0
3 years ago
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