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3 years ago

This equation shows the reaction that occurs when charcoal burns. What

2 answers:

8 0

The reaction is called exothermic because an exothermic process releases heat, causing the temperature of the immediate surroundings to rise and thats exactly what charcoal does when burned.

ikadub [295]3 years ago

5 0

Answer: C is correct,

Explanation:

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3 years ago

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3 years ago

What would diluting the vinegar do to the rate of a reaction between vinegar and sodium hydroxide? decrease the rate of reaction

GarryVolchara [31]

Vinegar is aceti acid diluted in water.

The reaction of vinegar with sodium hydroxide is:

CH3COOH + NaOH ---> CH3COONa + H2O

That is an acid-base reaction.

The speed of reaction is proportional to the concentrations of the reactants.

Then, given thatn when you dilute the vinegar you decrease the concentration of CH3COOH, the rate of reaction will decrease.

Answer: decrease the rate of reaction.

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3 years ago

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3 years ago

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Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, n, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.

$w_\text{max} = n \cdot F \cdot E_\text{cell}$ , where

n is the number of moles electrons transferred,
F is the Faraday's constant,
E $_\text{cell}$ is the cell potential,

n = 0.144 mol, as shown above, and

F = 96.486 kJ / ( $\text{V} \cdot \text{mol} \; \text{e}^{-}$ ).

Therefore,

$w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}$ .

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3 years ago