M<span>olar mass Hg = 200.5920g/mol </span>
<span>Hg = 24.1/200.5920 = 0.120mol </span>
<span>234.32K liquid to 25C (298.15K) liquid </span>
<span>h = (0.120)(28.0)(298.15 - 234.32) = 214.4688 J </span>
<span>234.32K liquid to 234.32K solid </span>
<span>h = (0.120)(2.29) = 0.2748 kj </span>
<span>total heat = 0.2145 + 0.2748 = 0.4893 kJ</span>
Answer:
0.1472 mol/L is the concentration of the barium hydroxide solution.
Explanation:
Mass of potassium hydrogen phthalate = 2.050 g
Molar mass of potassium hydrogen phthalate =
According to reaction , 2 moles of potassium hydrogen phthalate reacts with 1 mole of barium hydroxide, then 0.01004 moles of potassium hydrogen phthalate will :
of barium hydroxide
Moles of barium hydroxide = 0.005020 mol
Volume of the barium hydroxide solution = 34.10 mL = 0.03410 L
1 mL = 0.001 L
Molarity of the barium hydroxiude silution :
0.1472 mol/L is the concentration of the barium hydroxide solution.
This is false. Some plants are the same or at least very similar
Answer:
The answer to your question is: 0.118 moles of water
Explanation:
Data
moles of water = ?
Vol of O2= 1.6
Temp = 324°K
Pressure = 0.984 atm
R = 0.082 atm l / mol°K
Process
1.- Calculate the moles of O₂ using the ideal gas formula.
PV = nRT
n = 0.059 moles of oxygen
2.- Find the moles of water
2 moles of water ------------------ 1 mol of oxygen
x ------------------ 0.059 moles
x = (0.059 x 2) / 1
x = 0.118 moles of water
L think the answer is kc=:02:-3