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3 years ago

A group of analytical chemists are examining a compound. They find that it's composed of 34.4% iron and 65.6% chlorine by

Chemistry

2 answers:

Rina8888 [55]3 years ago

4 0

Answer:

B.FeCl₂

Explanation:

there is twice as much chlorine as there is iron

nasty-shy [4]3 years ago

4 0

Answer:

B.FeCl₂

Explanation:

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Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el

givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

$Cu^{2+}+2e^-\rightarrow Cu$

$2\times 96500=193000C$ is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

$14\times 1000g=14000g$ of copper is deposited by = $\frac{193000}{63.5}\times 14000=42551181 C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

$40.0=\frac{42551181 C}{t}\\\\t=1063779sec$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $1063779s\times \frac{1hr}{3600s}=295hr$

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0

3 years ago

Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (

madreJ [45]

Answer: a) chromium-52 : protons = 24, neutrons = 28

selenium - 80 : protons = 34, neutrons = 46

molybdenum-98: protons = 42, neutrons = 56

xenon-132: protons = 54, neutrons = 78

ytterbium-174 : protons = 70, neutrons = 104

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, number of protons = atomic number

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

a) chromium-52 :

Atomic number of Chromium is 24 hence number of protons = 24

52= 24+ Number of neutrons

Number of neutrons = 28

b) selenium - 80 :

Atomic number of selenium is 34 hence number of protons = 34

80 = 34 + Number of neutrons

Number of neutrons = 46

c) molybdenum - 98 :

Atomic number of molybdenum is 42 is hence number of protons = 42

98 = 42 + Number of neutrons

Number of neutrons = 56

d) xenon-132:

Atomic number of xenon is 54 hence number of protons = 54

132 = 54 + Number of neutrons

Number of neutrons = 78

e) ytterbium-174:

Atomic number of ytterbium is 70 and hence number of protons = 70

174 = 70 + Number of neutrons

Number of neutrons = 104

6 0

3 years ago

Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is

Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0

3 years ago

A gas-filled weather balloon with a volume of 65.0 L is released at sea level where conditions are745 torr and 25 ºC. The balloo

Blababa [14]

Answer:

It will reach to its maximum volume.

Explanation:

Using Ideal gas equation for same mole of gas as :-

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 65.0 mL

V₂ = ?

P₁ = 745 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 745 / 760 atm = 0.9803 atm

P₁ = 0.9803 atm

P₂ = 0.066 atm

T₁ = 25 ºC

T₂ = -5 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (25 + 273.15) K = 298.15 K

T₂ = (-5 + 273.15) K = 268.15 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{0.9803}\times {65.0}}{298.15}=\frac{{0.066}\times {V_2}}{268.15}$

Solving for V₂ as:-

$V_2=\frac{0.9803\times \:65.0\times 268.15}{298.15\times 0.066}$

$V_2=\frac{17086.38392}{19.6779}$

V₂ = 868 L

Given that:- V max = 835 L

<u>Thus, it will reach to its maximum volume.</u>

3 0

3 years ago

Which feature forms when magma cools beneath Earth's surface?

Snowcat [4.5K]

I’m pretty sure it’s Calderas

4 0

2 years ago

Read 2 more answers