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Dmitry_Shevchenko [17]
3 years ago
7

When antimatter interacts with an equal mass of ordinary matter, both matter and antimatter are converted completely into energy

, in the form of photons. In an antimatter-fueled spaceship, a staple of science fiction, the newly created photons are shot from the back of the ship, propelling it forward. Suppose such a ship has a mass of 2.00×10^6kg, and carries a mass of fuel equal to 4% of its mass, or 4.00×10^4kg of matter and an equal mass of antimatter.
Required:
What is the final speed of the ship, assuming it starts from rest, if all energy released in the matter-antimatter annihilation is transformed into the kinetic energy of the ship?
Physics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

  v = 5.88 10⁷ m / s

Explanation:

For this exercise we use the relation

          E = m c²

also indicate that all energy is converted into kinetic energy

          E = K = ½ (M-2m) v²

where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined

we substitute  

         m c² = ½ (M-2m) v²

        v² = 2 \frac{m}{M+2m} \ c^2

         

let's calculate

        v = \sqrt{2 \  \frac{4 \ 10^4 }{2 \ 10^6 + 2 \ 4 \ 10^4} \ (3 \ 10^8)^2}

         v = \sqrt{ 34.615 \ 10^{14}}

        v = 5.88 10⁷ m / s

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22. A race car accelerates from 0.0 m/s to 5 m/s with a displacement of 2.5 m. What is the
yanalaym [24]

Answer:

Option A

5 m/s^{2}

Explanation:

From fundamental equation of motion

v^{2}=u^{2}+2as where v is the final velocity, u is the initial velocity, a is the acceleration of the body and s is the displacement.

Since the initial velocity is zero

v^{2}=2as

Making acceleration, a the subject of the formula then

a=\frac {v^{2}}{2s}

Substituting 5 m/s for v and 2.5 m for s then

a=\frac {5^{2}}{2\times 2.5}=5 m/s^{2}

6 0
3 years ago
The worker’s pull on the handle of the cart can best be described as a force having
777dan777 [17]

Answer:

both magnitude and direction

Explanation:

The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.

  • This is a vector quantity
  • The force is channeled to move the cart in a specific direction.
  • Also, the pull on the cart can be quantified, and so it have magnitude.
  • Most physical properties either have magnitude or direction or both.

In this case, the worker is pulling the cart towards a specified direction.

Therefore, the fitting choice is both magnitude and direction.

8 0
4 years ago
Mass m is fired to the right at a speed of 7.0 m/s where it collides and becomes imbedded in mass M which is hanging from a rope
Tanya [424]

Answer:

V=0.28m/s, the combined mass will be 0.28m/s fast

h=0.00399m

Explanation:

Mass m is fired to the right at a speed of 7.0 m/s where it collides and becomes imbedded in mass M which is hanging from a rope. Mass m is 0.50kg and mass M is 12.0kg. a- How fast will the combined mass (m+M) be moving just after the collision? b- What is the maximum height the system (m+M) will reach?

step by step explanation:

from the principles of linear momentum which states that the total momentum before collision is equal to the total momentum after collision

momentum before collision=momentum after collision

notice that in this this case the collision is inelastic, owing to the fact that the two bodies stuck together after collision

mu+Mu2=(m+M)V

V=common velocity after collision

m=mass of the body fired

M=Mass hanging on the rope

u=velocity of the body

u2=velocity of the mass hanging on arope 0m/s

0.5*7+0=(0.5+12)V

3.5=12.5V

V=3.5/12.5

V=0.28m/s, the combined mass will be 0.28m/s fast

b. the maximum height reached after the impact

starting with the swing of the pendulum just after the collision until it reaches its maximum height. Conservation of mechanical energy applies here, so:

kinetic energy =potential energy

½ (m+M)V = (m+M)gh.

So, the speed of the system immediately after the collision is:

V = (2gh)½

0.28=(2*9.81*h)^0.5

0.0784=2*9.81h

h=0.00399m

8 0
4 years ago
What is shown by the pattern of iron filings around these two magnets?
nadya68 [22]

Answer:c

Explanation:

8 0
3 years ago
Read 2 more answers
A rock hanging from a string has a net force of zero acting on it ? true or false ?
sattari [20]

Answer:

true cuase it is true its not false

8 0
3 years ago
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