Answer:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Explanation:
Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:
(1)
Where:
, 
- Initial and final momemtums of the small object, measured in kilogram-meters per second.
, 
- Initial and final momentums of the big object, measured in kilogram-meters per second.
If we know that 
, 
and 
, then the final momentum of the big object is:
The magnitude of the large object's momentum change is:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.
F α Qq
If the charges are now half the initial charges:
<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q
The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
I believe the answer is 3 Newtons!
Answer:43.311 J
Explanation:
Given
mass of frame
mass of wheel 
radius of wheel
v=3.22 m/s
Moment of inertia of each wheel\left ( I\right )=\frac{1}{2}mr^2[/tex]
kinetic Energy of whole cycle=Kinetic energy of wheels and frame+rotational energy of Wheels
K.E.=39.037+4.274=43.311J
