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4 years ago

What is a material that reduces the flow of heat by conduction, convection, and radiation?

Physics

2 answers:

Vika [28.1K]4 years ago

5 0

Answer: Option (b) is the correct answer.

Explanation:

When a substance resists or does not allow any flow of electric current through it then it is known as an insulator.

For example, rubber, glass, paper etc are all insulators.

A conductor is a substance that allows easy passage of electric current through it.

A radiator is defined as the substance which emits radiations to transfer heat energy for heating and warming purpose.

A solar collector collects radiations that are passed from the Sun.

Thus, we can conclude that an insulator is a material that reduces the flow of heat by conduction, convection, and radiation.

Oksi-84 [34.3K]4 years ago

4 0

The answer is a insulator

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A peregrine falcon dives at a pigeon. The falcon starts with zero downward velocity and falls with the acceleration of gravity.

Reptile [31]

Answer:

t = 3.94 s

Explanation:

This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:

$h = v_{i}t + \frac{1}{2}gt^2$

where,

h = height = 76 m

vi = initial speed of falcon = 0 m/s

t = time required = ?

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$76\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\t^2 = \frac{(2)(76\ m)}{9.8\ m/s^2}\\\\t = \sqrt{ 15.49\ s^2}\\$

5 0

3 years ago

Convert 1 mm to meters using scientific notation. Include units in your answer.

irinina [24]

Answer: The answer in scientific notation with the unit included is (1 × 10^-3m.)

Explanation:

In the field of physics, when working with too large or too small numbers, such can be expressed with the use of scientific notation. This helps to eliminate huge or ambiguous numbers with significant units. It is written is such a way that the first number is greater than or equal to 1 and less than 10 which is then multiplied by a factor of 10.

Units are symbols that are used to represent a measurement For example the unit of meters is (m).

Converting 1mm to m:

1000millimeters = 1meter

1 millimetre = X

Making X the subject of formula,

X = 1 ×1 /1000

X = 0.001m

Therefore expressing X in scientific notation is

1 × 10^-3meter (m)

7 0

3 years ago

Why does the bottom of a swimming pool always appear shallower than it actually is<br>

emmainna [20.7K]

Answer:

The refraction of light at the surface of water makes ponds and swimming pools appear shallower than they really are.

Explanation:

so its just the refraction of light at the surface

8 0

3 years ago

Read 2 more answers

A student measures the diameter of a small cylindrical object and gets the following readings: 4.32, 4.35, 4.31, 4.36, 4.37, 4.3

Zinaida [17]

Answer:

a. $\bar{d}=4.34 cm$

b. $\sigma=0.023 cm$

c. $\rho=(0.0089\pm 0.00058) kg/cm^{3}$

Explanation:

a) The average of this values is the sum each number divided by the total number of values.

$\bar{d}=\frac{\Sigma_{i=1}^(N)x_{i}}{N}$

$x_{i}$ is values of each diameter
N is the total number of values. N=6

$\bar{d}=\frac{4.32+4.35+4.31+4.36+4.37+4.34}{6}$

$\bar{d}=4.34 cm$

b) The standard deviation equations is:

$\sigma=\sqrt{\frac{1}{N}\Sigma^{N}_{i=1}(x_{i}-\bar{d})^{2}}$

If we put all this values in that equation we will get:

$\sigma=0.023 cm$

Then the mean diameter will be:

$\bar{d}=(4.34\pm 0.023)cm$

c) We know that the density is the mass divided by the volume (ρ = m/V)

and we know that the volume of a cylinder is: $V=\pi R^{2}h$

Then:

$\rho=\frac{m}{\pi R^{2}h}$

Using the values that we have, we can calculate the value of density:

$\rho=\frac{1.66}{3.14*(4.34/2)^{2}*12.6}=0.0089 kg/cm^{3}$

We need to use propagation of error to find the error of the density.

$\delta\rho=\sqrt{\left(\frac{\partial\rho}{\partial m}\right)^{2}\delta m^{2}+\left(\frac{\partial\rho}{\partial d}\right)^{2}\delta d^{2}+\left(\frac{\partial\rho}{\partial h}\right)^{2}\delta h^{2}}$