Answer:
Radius of curvature of the mirror = 250 cm
Explanation:
Given:
Object distance from mirror = 250 cm (u=-250)
Object distance appears in mirror = 250 cm (v=-250)
Find:
Radius of curvature of the mirror
Computation:
Using mirror formula
1/f = 1/v + 1/u
1/f = 1/(-250) + 1/(-250)
f = (-250/2)
f = -125 cm or 125 cm
Radius of curvature of the mirror = 2(f)
Radius of curvature of the mirror = 2(125)
Radius of curvature of the mirror = 250 cm
The speed of the roller coater at the bottom of the hill is 31 m/s.
<h3>
Speed of the roller coater at the bottom of the hill</h3>
Apply the principle of conservation of mechanical energy as follows;
K.E(bottom) = P.E(top)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- v is the speed of the coater at bottom hill
- h is the height of the hill
- g is acceleration due to gravity
v = √(2 x 9.8 x 49)
v = 31 m/s
Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.
Learn more about speed here: brainly.com/question/6504879
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Answer:
A single component that can’t be separated
brainliest please ;)