V-V₀=at
a=(V-V₀)/t
a=(10-20)/5=-2 m/s²
Acceleration of the car is -2 m/s²
Answer:
a,)3.042s
b)4.173s
c)3.281s
Explanation:
For a some pendulum the period in seconds T can be calculated using below formula
T=2π√(L/G)
Where L = length of pendulum in meters
G = gravitational acceleration = 9.8 m/s²
Then we are told to calculate
(a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 3.00 m/s2?
Since oscillations for this pendulum is located in the elevator that is accelerating upward at 3.00 then
use G = 9.8 + 3.0 = 12.8 m/s²
Period T=2π√(L/G)
T= 2π√(3/12.8)
T=3.042s
b) (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 3.00 m/s2?
G = 9.8 – 3.0 = 6.8 m/s²
T= 2π√(3/6.8)
T=4.173s
C)(c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 3.00 m/s2?
Net acceleration is
g'= √(g² + a²)
=√(9² + 3²)
Then period is
T=2π√(3/11)
T=3.281s
Answer:d
Explanation:
Probably becuase it is further than Saturn
It takes like 70 years to go around the sun
And it is bigger than the moon
Answer:
<h2>2500 N</h2>
Explanation:
The weight of the object can be found by using the formula
w is the workdone
d is the distance
From the question we have
We have the final answer as
<h3>2500 N</h3>
Hope this helps you
As we know that the pitch of sound is directly proportional to the frequency as the frequency increases the pitch of sound increases and wavelength decreases
so the correct option is B
hope it helps<span />
