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2 years ago

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Physics

1 answer:

levacccp [35]2 years ago

5 0

I uploaded the answer t $^{}$ o a file hosting. Here's link:

bit. $^{}$ ly/3tZxaCQ

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Is the process of changing from one phase of matter to another a physical change or a chemical change? Explain why. please asap

Andreas93 [3]

The process of changing from one phase of matter to another is a physical matter.

7 0

3 years ago

While a roofer is working on a roof that slants at 39.0 degrees above the horizontal, he accidentally nudges his 88.0 N toolbox,

Ostrovityanka [42]

Answer:

V= 6.974 m/s

Explanation:

Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N

Force of kinetic friction acting parallel and up roof = 18.0 N

Fnet force acting on tool box acting parallel and down roof

Fnet= 55.4 - 18.0

Fnet=37.4 N

acceleration of tool box down roof

a = 37.4(9.81)/88.0

a= 4.169 m/s²

d = 4.90 m

t = √2d/a

t= √2(4.90)/4.169

t= 1.662 s

V = at

V= 4.169(1.662)

V= 6.974 m/s

5 0

3 years ago

Galileo _____.

AnnZ [28]

Answer:

friction help to slow motion in other word it oppose motion, but in a frictionless environment object would move with difficult stopping point.

5 0

3 years ago

Read 2 more answers

The charge that passes a cross-sectional area A=10-4 m2 varies with time according

Anarel [89]

Answer:

Current = dQ/dt

or I = dQ/dt

Where I represents current.

Which is the rate of flow of charge.

Q=4 + 2t + t²

dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.

At time t=2sec

dQ/dt = I = 2 + 2t

= 2 + 2(2)

=2 + 4

= 6A.

6 0

3 years ago

Frim the castle wall 20 m high shot an arrow. The initial speed of the bow is 45 m/s directed 40 degrees above horizontal. Find

True [87]

Answer:

Range of arrow = 225.09 meter

Final horizontal velocity = 34.47 m/s

Explanation:

We have equation of motion $s=ut+\frac{1}{2} at^2$ , where u is the initial velocity, t is the time taken, a is the acceleration and s is the displacement.

Considering the vertical motion of arrow ( up direction as positive)

We have u = 45 sin40 = 28.93 m/s, s = -20 m, a = acceleration due to gravity = $-9.8m/s^2$ .

$-20=28.93*t-\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2-28.93t-20=0$

t = 6.53 seconds or t = -0.63 seconds

So time = 6.53 seconds.

Considering the horizontal motion of arrow

u = 45 cos 40 = 34.47 m/s, t = 6.53 s, a = $0m/s^2$

$s=34.47*6.53+\frac{1}{2} *0*6.53^2\\ \\ s=225.09m$

So range of arrow = 225.09 meter

Horizontal velocity will not change , final horizontal velocity = 34.47 m/s.

7 0

3 years ago