Given Information:
Wavelength = λ = 39.1 cm = 0.391 m
speed of sound = v = 344 m/s
linear density = μ = 0.660 g/m = 0.00066 kg/m
tension = T = 160 N
Required Information:
Length of the vibrating string = L = ?
Answer:
Length of the vibrating string = 0.28 m
Explanation:
The frequency of beautiful note is
f = v/λ
f = 344/0.391
f = 879.79 Hz
As we know, the speed of the wave is
v = √T/μ
v = √160/0.00066
v = 492.36 m/s
The wavelength of the string is
λ = v/f
λ = 492.36/879.79
λ = 0.5596 m
and finally the length of the vibrating string is
λ = 2L
L = λ/2
L = 0.5596/2
L = 0.28 m
Therefore, the vibrating section of the violin string is 0.28 m long.
Answer:
3360 N
Explanation:
In a first-class lever, the effort force and load force are on opposite sides of the fulcrum.
The lever is 5 m long. The load force is 1.50 m from the fulcrum, so the effort force must be 3.50 m from the fulcrum.
The torques are equal:
Fr = Fr
(1440 N) (3.5 m) = F (1.5 m)
F = 3360 N
Displacement = (distance between start and end points) in the direction of (direction from start to end point). Distance = (11.3-3.38)= 7.92 m. Direction = the negative 'x' direction.
The number of cycles of a periodic wave per unit time is called the wave's "frequency". The height at which the peaks of the waves reside is the "amplitude".
Answer:
acceleration = 0.022 m/s^2
distance = 8.3 x 10^7 m
speed = 1.9 x 10 ^3 m/s
Explanation:
the parameters given are:
mass = 900kg
force = 20N
- from the formula force = mass x acceleration
acceleration = force / mass
acceleration = 20 / 900
acceleration = 0.022 m/s^2
- distance travelled in 1 day (86,400 seconds) = (1/2) x a x t^2
(1/2) x 0.022 x (86,400^2) = 8.3 x 10^7 m
- speed of the sun yatch (v) = a x t
0.22 x 86400 = 1.9 x 10 ^3 m/s
