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gizmo_the_mogwai [7]
3 years ago
9

WILL MARK BRAINLIEST!!!!!!!!

Physics
1 answer:
Dvinal [7]3 years ago
4 0
Answer:

The mass would remain the same and the weight would change

Explanation:

A rock is made out of matter; matter is never destroyed or made. Mass is the composition of matter in the rock. Mass is always constant.

Weight is a force, measured in Newton. The formula for weight (force) is;
force = mass \times acceleration
The force in this case is the weight and the acceleration is the gravitational pull. Since the mass is constant and the gravitational pull of earth and of the moon differs, the the force changes.
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The___is the time it takes for a wave to complete one cycle.
nignag [31]

Answer:

Period

Explanation:

we know that

The period of a wave is the time required for one complete cycle of the wave to pass by a point.

7 0
3 years ago
Read 2 more answers
I don’t understand I need help asap
hammer [34]
For the first question, you got them right, for the two you left blank, initial(beginning) velocity: 2 m/s the final velocity is: 12 m/s
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3 years ago
A rope.that is 1.50m long exhibits a standing wave pattern with 6 nodes if the frequency of the waves is 75.0 hz what is the vel
Sonja [21]
I think he answer is 34.32
4 0
3 years ago
45:56
Romashka-Z-Leto [24]

Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

7 0
3 years ago
A positively charged wire with uniform charge density +λ lies along the x-axis and a negatively charged wire with uniform charge
Kisachek [45]

Answer:

\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

Explanation:

The electric field created by an infinitely long wire can be found by Gauss' Law.

\int \vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}\\E2\pi r h = \frac{\lambda h}{\epsilon_0}\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 r} \^r

For the electric field at point (x,y), the superposition of electric fields created by both lines should be calculated. The distance 'r' for the first wire is equal to 'y', and equal to 'x' for the second wire.

\vec{E} = \vec{E}_1 + \vec{E}_2 = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) + \frac{-\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0 y}(\^y) - \frac{\lambda}{2\pi\epsilon_0 x}(\^x)\\\vec{E} = \frac{\lambda}{2\pi\epsilon_0}[\frac{1}{y}(\^y) - \frac{1}{x}(\^x)]

5 0
3 years ago
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