Answer:
false : In distance time graph,time is shown on the x -axis
Answer:
iittdhusludepeotlke is the only person who has ever seen a long distance friend from which he is the 3PM and 3AM and I
Explanation:
gt6e6ofkhithodzipfrhFfu0sa6eo5ostiatkstoss ragers the following 3AM is not the only one sentences you have to say about it is not an 2475232347 email from a substance abuse treatment center for a medical professional who is a substance addict or a physician in my life to be 367inches 4 to the end 6th
<span>22.5 newtons.
First, let's determine how much energy the stone had at the moment of impact. Kinetic energy is expressed as:
E = 0.5mv^2
where
E = Energy
m = mass
v = velocity
Substituting known values and solving gives:
E = 0.5 3.06 kg (7 m/s)^2
E = 1.53 kg 49 m^2/s^2
E = 74.97 kg*m^2/s^2
Now ignoring air resistance, how much energy should the rock have had?
We have a 3.06 kg moving over a distance of 10.0 m under a force of 9.8 m/s^2. So
3.06 kg * 10.0 m * 9.8 m/s^2 = 299.88 kg*m^2/s^2
So without air friction, we would have had 299.88 Joules of energy, but due to air friction we only have 74.97 Joules. The loss of energy is
299.88 J - 74.97 J = 224.91 J
So we can claim that 224.91 Joules of work was performed over a distance of 10 meters. So let's do the division.
224.91 J / 10 m
= 224.91 kg*m^2/s^2 / 10 m
= 22.491 kg*m/s^2
= 22.491 N
Rounding to 3 significant figures gives an average force of 22.5 newtons.</span>
Answer:
Explanation:
A = Area = 
B = Magnetic field = 1.7 T
= Angle that magnetic field makes with the plane of the loop = 
t = Time = 0.42 s
EMF is given by
The magnitude of the average emf induced in the loop is .
A because water has more volume when it's warmer
