water vapor. It is when water is evaporated. it can also be steam.
Answer:
37.1 kilograms of ammonia gas will be produced in this process
Explanation:
The percentage yield of the reaction is given by:
According to question
The percentage yield of the given industrial process = 74.0%
The given theoretical yield of ammonia gas = 50.1 kg
The experimental yield of ammonia gas = x
The percentage yield of the reaction is calculated a:
Solving for x, we get:
37.1 kilograms of ammonia gas will be produced in this process
Answer is: it is not possible, because orbital (azimunthal) quantum number cannot be 2.
The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
For principal quantum number n=2:
1) azimuthal quantum number (l) can be l = 0...n-1:
l = 0, 1.
The azimuthal quantum number determines its orbital angular momentum and describes the shape of the orbital.
2) magnetic quantum number (ml) can be ml = -l...+l.
ml = -1, 0, +1.
Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.
3) the spin quantum number (ms), is the spin of the electron.
ms = +1/2, -1/2.
That would be the NOBLE GASES (Helium, Neon, Argon, Krypton, Xenon, Radon). Because these elements have a filled outer shell (thus giving them the full octet that other elements crave), they are stable elements under normal circumstances and as such resist chemical combination.
Plz note that under special conditions, noble gases such as Xenon and Radon can form compounds (Xenon Fluoride and Oxide; Radon Fluoride)
