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Sergeeva-Olga [200]

3 years ago

7

If you could change one property of a substance ( solid, liquid, and gas) you have to use in your daily life, what would it be a

nd why?
Please hurry
I will give you BRAINLIEST!!!!!!
And pleaseee write 5 sentences why??

2 answers:

MariettaO [177]3 years ago

7 0

Water into ice cubes, because lukewarm water is nasty.

shepuryov [24]3 years ago

4 0

Answer

Soap into a liquid

Explanation:

You might be interested in

Which factors are used to calculate the kinetic energy of an object? Check all that apply.

Verizon [17]

Gravity and velocity

8 0

3 years ago

A ski jumper starts with a horizontal take-off velocity of 25 m/s and lands on a straight landing hill inclined at 30o. Determin

melamori03 [73]

Answer:

0.34s, 8.5m,31.89m

Explanation:

The above motion defines a projectile motion.

Now the athletes lands on a cliff 30° to the horizontal this means the velocity at that point would be 25m/s cos30°

Now from Newton's law of motion.

The body would be decelerating so,

V = u - gt

Where u is initial velocity and v is final velocity. g is acceleration of free fall due to gravity.

Hence,

V-U/ -g = t

Hence 25cos30 - 25/ -9.8 = 0.34s.

2.Now the length of the jump is defined as the total horizontal distance which is marked off by the horizontal velocity and time taken for take off and landing.

Hence Distance,S = u × t

25 ×0.34 =8.5m.

3. The maximum height is defined that at that point the Final velocity is 0m/s

Now the initial velocity is 25m/s

From Newton's law that;

V2= U2 -2gH; where U and V are initial and final velocity and H is height.

Hence H = V2-U2/-2g

=(0)^2- (25)^2/ -2×9.8

= -625/-19.6 =31.89m

8 0

3 years ago

A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.

Veronika [31]

Answer:

A) ω = 6v/19L

B) K2/K1 = 3/19

Explanation:

Mr = Mass of rod

Mb = Mass of bullet = Mr/4

Ir = (1/3)(Mr)L²

Ib = MbRb²

Radius of rotation of bullet Rb = L/2

A) From conservation of angular momentum,

L1 = L2

(Mb)v(L/2) = (Ir+ Ib)ω2

Where Ir is moment of inertia of rod while Ib is moment of inertia of bullet.

(Mr/4)(vL/2) = [(1/3)(Mr)L² + (Mr/4)(L/2)²]ω2

(MrvL/8) = [((Mr)L²/3) + (MrL²/16)]ω2

Divide each term by Mr;

vL/8 = (L²/3 + L²/16)ω2

vL/8 = (19L²/48)ω2

Divide both sides by L to obtain;

v/8 = (19L/48)ω2

Thus;

ω2 = 48v/(19x8L) = 6v/19L

B) K1 = K1b + K1r

K1 = (1/2)(Mb)v² + Ir(w1²)

= (1/2)(Mr/4)v² + (1/3)(Mr)L²(0²)

= (1/8)(Mr)v²

K2 = (1/2)(Isys)(ω2²)

I(sys) is (Ir+ Ib). This gives us;

Isys = (19L²Mr/48)

K2 =(1/2)(19L²Mr/48)(6v/19L)²

= (1/2)(36v²Mr/(48x19)) = 3v²Mr/152

Thus, the ratio, K2/K1 =

[3v²Mr/152] / (1/8)(Mr)v² = 24/152 = 3/19

3 0

3 years ago

Electricity may be categorized as static or current. how are these two types of energy different

arlik [135]

Hello!

Static electricity occurs due to an imbalance in positively and negatively charged atoms. An example of this is when you take your clothes out of the dryer, and feel a slight sting when touching them. Another example of static electricity is lightning.

Current electricity occurs when there is a constant flow of electrons, such as in plug-operated machinery or anything operated using a battery. :)

4 0

3 years ago

In the Olympic shotput event, an athlete throws the shot with an initial speed of 13.0 m/s at a 47.0° angle from the horizontal.

MariettaO [177]

Answer:

18.7 m

Explanation:

$v_{o}$ = initial speed of the shot = 13 m/s

θ = angle of launch from the horizontal = 47 deg

Consider the motion along the vertical direction

$v_{oy}$ = initial velocity along vertical direction = 13 Sin47 = 9.5 m/s

$a_{y}$ = acceleration along the vertical direction = - 9.8 m/s²

y = vertical displacement = - 1.80 m

t = time of travel

Using the kinematics equation

$y=v_{oy} t+(0.5)a_{y} t^{2}$

- 1.80 = (9.5) t + (0.5) (- 9.8) t²

t = 2.11 s

Consider the motion along the horizontal direction

x = horizontal displacement of the shot

$v_{ox}$ = initial velocity along horizontal direction = 13 Cos47 = 8.87 m/s

$a_{x}$ = acceleration along the horizontal direction = 0 m/s²

t = time of travel = 2.11 s

Using the kinematics equation

$x=v_{ox} t+(0.5)a_{x} t^{2}$

x = (8.87) (2.11) + (0.5) (0) (2.11)²

x = 18.7 m

8 0

3 years ago