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Advocard [28]
3 years ago
9

Jill is pushing a box across the floor. Which represents the upward force perpendicular to the floor?

Physics
1 answer:
AfilCa [17]3 years ago
7 0
I think it fb I’m not really sure
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You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
nekit [7.7K]

There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.  

Answer:

d=3.67 m

Explanation:

Height of building=46.0 m

First we need to find time taken by egg to reach 1.80 m above the surface

So to find time use below equation

S=vt+\frac{1}{2} gt^{2}\\ (46.0-1.80)m=(om/s)t+\frac{1}{2}(9.8m/s^{2} )t^{2}\\t=\sqrt{\frac{(46.0-1.80)m}{4.9} }\\ t=3.06s

As velocity 1.20m/s is given and we have find time.So we can easily find the distance

So

distance=velocity*time\\d=v*t\\d=(1.20m/s)*(3.06s)\\d=3.67m

3 0
3 years ago
8. You push downward on a box with a force of 750 N. The box is on a flat horizontal surface for which the coefficient of static
natima [27]

Answer:

The mass of the heaviest box you will be able to move with this applied force = 61.4 kg

Explanation:

From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.

For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.

Resolving the applied force into horizontal and vertical components,

Fₓ = 750 cos 25° = 679.73 N

Fᵧ = 750 sin 25° = 316.96 N

Doing a force balance in the vertical axis,

N = (mg + 316.96)

Frictional force = μN = μ (mg + 316.96)

μ = 0.74, g = 9.8 m/s²

Frictional force = Fᵧ

μ (mg + 316.96) = 679.73

0.74(9.8m + 316.96) = 679.73

7.252m + 234.5504 = 679.73

7.252m = 679.73 - 234.5504 = 445.1796

m = (445.1796/7.252)

m = 61.4 kg

Hope this Helps!!!

6 0
3 years ago
Un recipiente con una capacidad de 25L contiene un gas a una presión de 7,5 atm. Calcula la nueva presión a la que se verá somet
amid [387]

Responder:  

18.75 atmósferas  

Explicación:  

Paso uno:  

datos dados

volumen inicial V1 = 25L

Presión inicial P1 = 7.5 atm

volumen final V2 = 10L

presión final P2 = ??

Segundo paso:

Aplicando la expresión de gas que relaciona el volumen y la presión, es decir

P1V1 = P2V2

sustituyendo nuestros datos tenemos

7.5 * 25 = P2 * 10

187.5 = P2 * 10

divide ambos lados por 10

P2 = 187.5 / 10

P2 = 18.75 atmósferas

<em><u>La presión final es de 18.75 atm.</u></em>

5 0
3 years ago
The law of conservation of matter states that during a chemical reaction, the amount of matter ​
mixas84 [53]

Answer:

The law of conservation of matter says that in chemical reactions, the total mass of the products must equal the total mass of the reactants.

7 0
3 years ago
Why is nitrogen or helium filled in a filament lamp??
nirvana33 [79]
Argon<span> gas is used in fluorescent and incandescent light </span>bulbs<span> to stop the oxygen in the light </span>bulbs<span> from corroding the hot tungsten filament.The use of </span>argon<span> in light</span>bulbs<span> prevents the evaporation of the tungsten filaments, which results in increased light </span>bulb<span> life.</span>
7 0
3 years ago
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