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Explanation:
<em>Are</em><em> </em><em>the</em><em> </em><em>compounds</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>ionic</em><em> </em><em>bonding</em><em> </em><em>or</em><em> </em><em>electronic</em><em> </em><em>bonding</em><em>.</em><em> </em><em>They</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>transferring</em><em> </em><em>the</em><em> </em><em>electron</em><em> </em><em>form</em><em> </em><em>one</em><em> </em><em>element's</em><em> </em><em>valance</em><em> </em><em>shell</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>element's</em><em> </em><em>shell</em><em>.</em>
<em><u>i</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
V_f = 287.04 mL
Explanation:
We are given the initial/original volume of the glycerine as 285 mL.
Now, after it is finally cooled back to 20.0 °C , its volume is given by the formula;
V_f = V_i (1 + βΔT)
Where;
V_f is the final volume
V_i is the original volume = 285 mL
β is the coefficient of expansion of glycerine and from online tables, it has a value of 5.97 × 10^(-4) °C^(−1)
Δt is change in temperature = final temperature - initial temperature = 32 - 20 = 12 °C
Thus, plugging in relevant values;
V_f = 285(1 + (5.97 × 10^(-4) × 12))
V_f = 287.04 mL
Answer:
4.9N
Explanation:
The formula for weight is F = ma.
You plug in the mass of 0.5kg and an acceleration of 9.8 to get
F = (0.5)(9.8)
F = 4.9N
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