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4 years ago

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A system consists of three particles with these masses and velocities: mass 3.00 kg, moving north at 3.00 m/s; mass 4.00 kg, mov

ing south at 3.70 m/s; and mass 7.00 kg, moving north at 2.00 m/s. What is the total momentum of the system? Take north as the positive axis. Enter a positive answer if the total momentum is due north and a negative answer if the total momentum is due south.

1 answer:

lions [1.4K]4 years ago

7 0

Answer:

the total momentum is 8 .2 kg m/s in north direction.

Explanation:

given,

mass(m₁) 3.00 kg, moving north at v₁ = 3.00 m/s

mass(m₂) 4.00 kg, moving south at v₂ = 3.70 m/s

mass(m₃) 7.00 kg, moving north at v₃ = 2.00 m/s

north as the positive axis

south as the negative axis

now

total momentum = m₁v₁ + m₂ v₂ + m₃ v₃

total momentum = 3 x 3 - 4 x 3.7 + 7 x 2

= 9 - 14.8 + 14

= 8 .2 kg m/s

hence, the total momentum is 8 .2 kg m/s in north direction.

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Generally the energy of the incident light is mathematically represented as

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