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kenny6666 [7]
2 years ago
8

El lago Don Juan, es considerado el más salino de la Tierra, contiene en sus aguas 3.72 mol/kg de cloruro de calcio (CaCl2) y 0.

5 mol/kg de cloruro de sodio (NaCl). ¿Cuántos gramos de estas sales contiene por cada kilogramo de agua?
Chemistry
1 answer:
Alex73 [517]2 years ago
6 0

Answer:

412.8 \frac{gCaCl_2}{kg\ agua} \\\\29 \frac{gNaCl}{kg\ agua}

Explanation:

¡Hola!

En este caso, dado que se nos dieron las moles de cada sal por cada kilogramo de agua, es necesario para nosotros calcular los gramos por medio de la masa molar de estas, que son 110.98 g/mol y 58.44 g/mol respectivamente.

De este modo, realizamos las conversiones de moles a masa como se muestra a continuacion:

3.72\frac{molCaCl_2}{kg\ agua} *\frac{110.98gCaCl_2}{1molCaCl_2}=412.8 \frac{gCaCl_2}{kg\ agua} \\\\0.5\frac{molNaCl}{kg\ agua} *\frac{58.44gNaCl}{1molNaCl}=29 \frac{gNaCl}{kg\ agua}

¡Saludos!

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Answer:

c=2.0769\  \frac{J}{g\ \textdegree C}

Explanation:

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q=mc\bigtriangleup T

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q=mc\bigtriangleup T\\\\c=\frac{q}{m\bigtriangleup T}\\\\\bigtriangleup T=(57-32)\textdegree C=25\textdegree C\\\\\therefore c=\frac{6.75\times 10^4J}{1.3\times 1000\ g\times 25\textdegree  C}\\\\=2.0769 \ \frac{J}{g\ \textdegree C}

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3 years ago
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3 years ago
A gas balloon has a volume of 80.0 mL at 300K, and a pressure of 50.0 kPa. If the pressure changes to 80 kPa and the temperature
fomenos

Answer:  The new volume is 53.3 ml

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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3 years ago
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In a single replacement reaction between 2.57 moles Aluminum and 3.59 moles of Hydrochloric acid, how many moles of Hydrogen can
Alenkasestr [34]

Answer:

1.795 mole of H2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

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Step 2:

Determination of the limiting reactant.

From the balanced equation above,

2 moles of Al reacted with 6 moles

Therefore, 2.57 moles of Al will react with = (2.57 x 6)/2 = 7.71 moles of HCl.

From the calculation made above, it will require a higher amount of HCl than what was given to react completely with 2.57 moles of Al. Therefore, HCl is the limiting reactant and Al is the excess reactant.

Step 3:

Determination of the number of mole H2 produced from the reaction.

Here, we shall be using the limiting reactant because it will produce the maximum yield of the reaction since all of it were consumed by the reaction.

The limiting reactant is HCl and the amount of H2 produce can be obtained as follow:

From the balanced equation above,

6 moles of HCl reacted to produce 3 moles of H2.

Therefore, 3.59 moles of HCl will produce = (3.59 x 3)/6 = 1.795 mole of H2.

From the calculations made above, 1.795 mole of H2 is produced from the reaction.

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