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andrew-mc [135]
3 years ago
7

What came first the chicken or the egg

Physics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

The Egg

Explanation:

personally the Chicken who would lay the egg would have to come from an Egg itself, then It would have to grow up and then Produce an egg that will produce a chicken and so on.

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Frequency = 1/time period = 1/0.05 = 20s^-1. 
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Multiple Choice
Andreas93 [3]

Acceleration of car is  4m/s²

Acceleration of truck is 2m/s²

Explanation:

Given parameters:

Force on the car and truck = 12000N

Mass of car = 3000kg

Mass of truck = 6000kg

Unknown:

Acceleration of car = ?

Acceleration of truck = ?

Solution:

Force is product of mass and acceleration. It is a push or a pull exerted on a body.

      Force = mass x acceleration

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Acceleration of truck = \frac{12000}{6000} = 2m/s²

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3 0
3 years ago
Your name is Galileo Galilei and you toss a weight upward at 20 feet per second from the top of the Leaning Tower of Pisa (heigh
Veseljchak [2.6K]

Answer:

a) v(t) = -32.2 ft/s² · t + 20 ft/s

b) h(t) = 184 ft + 20 ft/s · t - 16.1 ft/s² · t²

c) The weight will reach its maximum height after 0.62 s. The maximum height will be 190 feet.

Explanation:

Hi there!

a) Since the only force that acts on the weight is the gravity force, the object is under a constant downward acceleration g = -32.2 ft/s² (it is negative because we consider the upward direction as positive). The acceleration is the variation of the velocity over time (dv/dt). Then:

dv/dt = g

Separating variables:

dv = g dt

Integrating from the initial velocity, v0, to v and from t = 0 to t, we obtain:

v - v0 = g t

v = g t + v0

Then:

v(t) = -32.2 ft/s² · t + 20 ft/s

b) The velocity of the weight is the variation of the height over time:

dh/dt = v(t)

dh/dt = g t + v0

Separating varibles:

dh = g t dt + v0 dt

Integrating from initial height, h0, to h and from t = 0 to t:

h - h0 = 1/2 · g · t² + v0 · t

h = h0 + v0 · t + 1/2 · g · t²

Then:

h(t) = 184 ft + 20 ft/s · t - 1/2 · 32.2 ft/s² · t²

h(t) = 184 ft + 20 ft/s · t - 16.1 ft/s² · t²

c) When the weight reaches its maximum height, its velocity will be zero. Then, using the equation of velocity we can obtain the time at which the weight is at the maximum height:

v(t) = -32.2 ft/s² · t + 20 ft/s

0 = -32.2 ft/s² · t + 20 ft/s

-20 ft/s/ -32.2 ft/s² = t

t = 0.62 s

The weight will reach its maximum height after 0.62 s.

The maximum height will be h(0.62 s):

h(t) = 184 ft + 20 ft/s · t - 16.1 ft/s² · t²

h(0.62 s) = 184 ft + 20 ft/s · (0.62 s) - 16.1 ft/s² · (0.62 s)²

h(0.62 s) = 190 ft

The maximum height will be 190 feet.

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Answer:

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