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3 years ago

Air is composed of nitrogen oxygen and based on that information air can be described as

Chemistry

1 answer:

Vilka [71]3 years ago

4 0

Answer:

Air can be described as: Mass and Mixture of Gases

Mass is defined as how much stuff an object contains - and by stuff, I mean matter, like atoms and molecules. And even though you can't see it, air has a lot of atoms and molecules. Air is a gas (as opposed to a liquid or a solid) and contains about 78% nitrogen, 21% oxygen, and 1% argon.

Explanation:

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A sample of a substance has a mass of 27.3 grams and a volume of 7.0 centimeters3. The density of this substance is

lora16 [44]

Answer:

The density of the substance is 3.9 grams per cubic centimeter.

Explanation:

Given mass=27.3 grams

volume=7 cubic centimeter

We need to find the density.

Density of a substance can be calculated by dividing mass of substance by volume of a substance

$Density\ =\ \frac{mass}{volume}$

$\\Therefore\ density\ =\ \frac{27.3}{7} \ =\ 3.9\ \frac{gm}{cm^3}$

Hence Density of the substance is $3.9gm/cm^3$ .

4 0

3 years ago

Suppose you have 15.0 ml of zinc. What volume of aluminum would have the same mass as the zinc?

Black_prince [1.1K]

Answer:

$\large \boxed{\text{41.2 cm}^{3}}$

Explanation:

1. Mass of zinc

The density of zinc is 7.14 g/cm³

D = m/V

$\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\$

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

$\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}$

5 0

3 years ago

3. What is the mass % of a solution that contains 36g KCl in 475g of water?

stira [4]

Answer:

%KCl = 7.05%

%Water = 92.95%

Explanation:

Step 1: Given data

Mass of KCl (solute): 36 g

Mass of water (solvent): 475 g

Step 2: Calculate the mass of the solution

The mass of the solution is equal to the sum of the masses of the solute and the solvent.

m = 36 g + 475 g = 511 g

Step 3: Calculate the mass percentage of the solution

We will use the following expression.

%Component = mComponent/mSolution × 100%

%KCl = 36 g/511 g × 100% = 7.05%

%Water = 475 g/511 g × 100% = 92.95%

7 0

3 years ago

What is the heat needed to raise the temperature of 24.7 kg silver from 14.0 degrees Celsius to 30.0 degrees Celsius? Specific h

ELEN [110]

Answer:

$Q=93.3kJ$

Explanation:

Hello,

In this case, by knowing that the heat due to a change of temperature is given by:

$Q=mCp\Delta T$

Whereas Q accounts for the heat, m for the mass, Cp the heat capacity and ΔT for the change in temperature. In such a way the required heat results:

$Q=24.7kg*236\frac{J}{kg^oC}*(30.0-14.0)^oC*\frac{1kJ}{1000J} \\Q=93.3kJ$

Best regards.

8 0

3 years ago

How many atom of oxygen are in 2mole of O2

GenaCL600 [577]

Answer:

12.044 × 10²³ atoms of oxygen

Explanation:

Given data:

Number of atoms of oxygen = ?

Moles of oxygen = 2 mol

Solution:

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms of oxygen

2 mole × 6.022 × 10²³ atoms of oxygen / 1 mole

12.044 × 10²³ atoms of oxygen

3 0

3 years ago