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slamgirl [31]
2 years ago
9

Blood test can be used to check a person's blood glucose and hormone levels. The tabular column given below shows the result of

two blood tests carried out on three people to check their blood glucose levels. Person 1 is healthy.
A:- Compare the glucose levels of person 1 with the glucose levels of person 2 after fasting for 12 hours.

B:- Compare the glucose levels of person 3 with the glucose levels of person 1, 2 hours after drinking 75g glucose.

C:- Person 3 cannot be produce the hormone that control blood glucose levels. State the hormone that person 3 cannot produce.

( THE ORDER OF THE PHOTO IS:- person 1, and person 2, and person 3)​


Pls it is urgent
Chemistry
1 answer:
Anastasy [175]2 years ago
3 0

Answer:

Explanation:

1) person 2 had a slightly higher blood glucose level than person 1 after fasting 12 hrs (0.2mmols)

2) person 3 has a much higher blood glucose level than person 1 after taking glucose (5.6mmols)

3) insulin

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Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
Elza [17]

Answer: 2.49^0C

Explanation:

Depression in freezing point is:

T_f^0-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = freezing point of solution = ?

T^o_f =  freezing point of solvent (cyclohexane) = 6.50^oC

k_f =  freezing point constant  of  solvent (cyclohexane)  = 20.0^oC/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute (biphenyl) = 0.771 g

w_1 = mass of solvent (cyclohexane) = 25.0 g

M_2 = molar mass of solute (biphenyl) =

Now put all the given values in the above formula, we get:

(6.50-T_f)^oC=1\times (20.0^oC/m)\times \frac{(0.771g)\times 1000}{154\times (25.0g)}

(6.50-T_f)^oC=4.01

T_f=2.49^0C

Therefore, the freezing point of a solution made by dissolving 0.771 g of biphenyl in 25.0 g of cyclohexane is 2.49^0C

4 0
3 years ago
What would be the final temperature of a 73.174g sample
madreJ [45]

The final temperature is -138 °C.

Explanation:

Using the equation of specific heat

Q = m*c* del T

We can easily find the final temperature of a 73.174 g of copper sample. As we know that specific heat is the amount of energy required to raise the temperature of the object to 1°C.

The specific heat of copper is known as 0.387 J/g°C and the initial temperature is said as 102 °C . The mass is given as 73.174 g. The heat released is 6800 J.

Since the heat is released the Q value will be negative.

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3 0
3 years ago
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Explanation:

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2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

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