Answer:
Im not sure what you want it to be rounded but heres the answers:
Whole number: 98
Tenths: 98.5
Hundredths: 98.49
Thousandths: 98.489
Step-by-step explanation:
Answer:
![\large { \boxed{\sf x = -4}](https://tex.z-dn.net/?f=%5Clarge%20%7B%20%5Cboxed%7B%5Csf%20x%20%3D%20-4%7D)
Explanation:
Original Expression:
![\rightarrow \sf x + 5 = 5 - 0 - 6 + 2](https://tex.z-dn.net/?f=%5Crightarrow%20%20%5Csf%20x%20%2B%205%20%20%3D%205%20-%200%20-%206%20%2B%202)
Subtract '5' from both sides:
![\sf \rightarrow x+5-5=5-0-6+2-5](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20x%2B5-5%3D5-0-6%2B2-5)
Simplify the following:
![\sf \rightarrow x=-0-6+2](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20x%3D-0-6%2B2)
Add/Subtract integers:
![\sf \rightarrow x=-4](https://tex.z-dn.net/?f=%5Csf%20%5Crightarrow%20x%3D-4)
Answer:
0000000000.00001
Step-by-step explanation:
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Answer: the solution to the inequality is -3 < x < 4. Graphically, this should be (2)
Step-by-step explanation:Note that x^2 - x - 12 factors to (x - 4)(x + 3) < 0, so we have:
(x - 4)(x + 3) < 0.The only way for (x - 4)(x + 3) to be negative is if x - 4 and x + 3 have opposite signs. This only occurs when:
(i) x - 4 < 0 AND x + 3 > 0
==> x < 4 AND x > -3; both occur when -3 < x < 4.
(ii) x - 4 > 0 and x + 3 < 0, which cannot happen at the same time.
1st box: 2a (subtract 2a from both sides)
2nd box: 3 (add 3 to both sides)
3rd box: 10 (add 7+3)
4th and 5th box: 2 (divide both by 2)
6th box: 5 (10/2=5)