Give the product expected when the following alcohol reacts with pyridinium chlorochromate (PCC). (Assume that PCC is present in
1 answer:
Answer:
Kindly check the explanation section.
Explanation:
Based on the description of the reacting -OH group containing Compound, the drawing of the chemical compound is given in the attached picture.
So, without mincing words let's dive straight into the solution to the question.
The reaction between the OH containing compound and PCC is an oxidation reaction.
Looking at the carbon number 1 which the first OH group and CH3 are attached to. Oxidation can not occur here as tertiary alcohol can not be oxidize.
Hence, the second OH will be oxidized into a carbonyl group, C = O. Kindly note that when alcohol oxidizes it turns into an aldehyde.
The equation for the reaction is also given the the attached picture.
You might be interested in
Answer:
158 L.
Explanation:
What is given?
Pressure (P) = 1 atm.
Temperature (T) = 112 °C + 273 = 385 K.
Mass of methane CH4 (g) = 80.0 g.
Molar mass of methane CH4 = 16 g/mol.
R constant = 0.0821 L*atm/mol*K.
What do we need? Volume (V).
Step-by-step solution:
To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:
Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.
So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:
So, in this case, n=5.
Now, let's solve for 'V' and replace the given values in the ideal gas law equation:
The volume would be 158 L.