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Answer:
Three halogens:
Fluorine, chlorine, bromine.
Explanation:
Halogens are present in group seventeen of periodic table.
Their are five elements in this group fluorine, chlorine, bromine, iodine, astatine.
Three halogens:
Fluorine, chlorine, bromine.
All these share common properties such as,
All of these have seven valance electrons.
When combine with hydrogen they form acids.
H₂ + Cl₂ → 2HCl
All of these are toxic in nature.
They are highly electronegative and most reactive elements.
When combine with metals they form salts such as sodium chloride, magnesium bromide.
2Na + Cl₂ → 2NaCl
2Na + Br₂ → 2NaBr
Mg + Br₂ → MgBr₂
Mg + Cl₂ → MgCl₂
We calculate the molar concentration [Cl⁻] using stoichiometry. MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.68 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.4 M
The answer to this question is [Cl⁻] = 1.4 M
Answer:
0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.
Explanation:
We are given with a mixture of sand and table sugar. The mixture has a mas s of 3.84 grams. After recovery, it was found out that there is 1.43 grams of sand. The amount of table sugar then is 3.84-1.43 or 2.41 grams. This is equal to 2.41/3.84 or 62.76% by mass/
