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3 years ago

Some mechanical advantages is lost to friction true or false

Physics

2 answers:

cupoosta [38]3 years ago

6 0

Answer:

I THINK it would be False.

Talja [164]3 years ago

3 0

Answer:

las respuestas es falso..... Mmm

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1. George Eliot pulls on a curtain string. If the curtain has a mass of 1.2 kg and she can pull

nekit [7.7K]

Answer:

F = 4.8 N

Explanation:

Given that,

Mass of the curtain, m = 1.2 kg

Acceleration of the pull, a = 4 m/s²

We need to find the force she exerts on the curtain.

We know that,

F = ma

Put al the values,

F = 1.2 kg × 4 m/s²

= 4.8 N

So, the force is 4.8 N.

6 0

3 years ago

A smooth wooden block is placed on a smooth wooden tabletop. You find that you must exert a force of 22.0 N to keep this 7.00 kg

xxMikexx [17]

Answer:

B . 68.7 N

Explanation:

Given in the question that;

Force = 22 N

Mass = 7.0 kg

Velocity = 4.0 m/s

Gravitational force is the weight of wooden block , calculated as mass times acceleration due to gravity.

F= m* a

F= 7 * 9.81

F= 68.67 N

F= 68.7 N

7 0

3 years ago

Which players are usually the tallest on their team, and stay close to the basket so they can shoot and rebound the ball?

alexdok [17]

Answer:

Center

Explanation:

The center is the tallest player on each team, playing near the basket. On offense, the center tries to score on close shots and rebound. But on defense, the center tries to block opponents' shots and rebound their misses.

7 0

3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

An object starts from rest and falls freely for 40. meters near the surface of planet P. If the time of fall is 4.0 seconds, wha

Sergeu [11.5K]

Let's use the equations for rectilinear motion. One particular equation is:

d = v₀t +(1/2)at²

Since it has been mentioned that the object starts from rest, then v₀ = 0. Substituting the values,

40 m = (0)(4 s) + (1/2)(a)(4 s)²
Solving for a,
a = 5 m/s²

<em>Therefore, the acceleration due to gravity is 5 m/s².</em>

6 0

4 years ago